Javascript 如何删除多个子元素的属性?
我有系统生成的链接,我手动隐藏。现在我想删除链接的标题属性,这些属性是在用户复制周围文本时复制的Javascript 如何删除多个子元素的属性?,javascript,attributes,Javascript,Attributes,我有系统生成的链接,我手动隐藏。现在我想删除链接的标题属性,这些属性是在用户复制周围文本时复制的 <html> <head> <script type="text/javascript"> var getElementsByClassName = function (className, tag, elm){ if (document.getElementsByClassName) { getElementsByClassNa
<html>
<head>
<script type="text/javascript">
var getElementsByClassName = function (className, tag, elm){
if (document.getElementsByClassName) {
getElementsByClassName = function (className, tag, elm) {
elm = elm || document;
var elements = elm.getElementsByClassName(className),
nodeName = (tag)? new RegExp("\\b" + tag + "\\b", "i") : null,
returnElements = [],
current;
for(var i=0, il=elements.length; i<il; i+=1){
current = elements[i];
if(!nodeName || nodeName.test(current.nodeName)) {
returnElements.push(current);
}
}
return returnElements;
};
}
else if (document.evaluate) {
getElementsByClassName = function (className, tag, elm) {
tag = tag || "*";
elm = elm || document;
var classes = className.split(" "),
classesToCheck = "",
xhtmlNamespace = "http://www.w3.org/1999/xhtml",
namespaceResolver = (document.documentElement.namespaceURI === xhtmlNamespace)? xhtmlNamespace : null,
returnElements = [],
elements,
node;
for(var j=0, jl=classes.length; j<jl; j+=1){
classesToCheck += "[contains(concat(' ', @class, ' '), ' " + classes[j] + " ')]";
}
try {
elements = document.evaluate(".//" + tag + classesToCheck, elm, namespaceResolver, 0, null);
}
catch (e) {
elements = document.evaluate(".//" + tag + classesToCheck, elm, null, 0, null);
}
while ((node = elements.iterateNext())) {
returnElements.push(node);
}
return returnElements;
};
}
else {
getElementsByClassName = function (className, tag, elm) {
tag = tag || "*";
elm = elm || document;
var classes = className.split(" "),
classesToCheck = [],
elements = (tag === "*" && elm.all)? elm.all : elm.getElementsByTagName(tag),
current,
returnElements = [],
match;
for(var k=0, kl=classes.length; k<kl; k+=1){
classesToCheck.push(new RegExp("(^|\\s)" + classes[k] + "(\\s|$)"));
}
for(var l=0, ll=elements.length; l<ll; l+=1){
current = elements[l];
match = false;
for(var m=0, ml=classesToCheck.length; m<ml; m+=1){
match = classesToCheck[m].test(current.className);
if (!match) {
break;
}
}
if (match) {
returnElements.push(current);
}
}
return returnElements;
};
}
return getElementsByClassName(className, tag, elm);
};
function notitle() {
var mylist=document.getElementsByClassName("notitle");
for (j=0; j<mylist.length; j++) {
var listitems= mylist[j].getElementsByTagName("a");
for (i=0; i<listitems.length; i++) {
listitems[i].removeAttribute("title");
}
}
}
</script>
</head>
<body onLoad="notitle()">
<p>Before hidden link 1: <span class="notitle" style="display: none;">
<a href="#Foo" title="Foo">This link should have no title attribute</a>
</span>After hidden link 1.</p>
<p>Before hidden link 2: <span class="notitle" style="display: none;">
<a href="#Foo" title="Foo">This link should have no title attribute</a>
</span>After hidden link 2.</p>
<p>Before hidden link 3: <span class="notitle" style="display: none;">
<a href="#Foo" title="Foo">This link should have no title attribute</a>
</span>After hidden link 3.</p>
</body>
</html>
var getElementsByClassName=函数(类名、标记、elm){
if(document.getElementsByClassName){
getElementsByCassName=函数(类名、标记、elm){
elm=elm | |文件;
var elements=elm.getElementsByClassName(className),
nodeName=(标记)?新的RegExp(“\\b”+tag+”\\b,“i”):null,
returnElements=[],
现在的
对于(var i=0,il=elements.length;i您的方法是正确的,但您多次使用相同的id。请确保id不同,或者使用通用类名并以这种方式检索元素。这是因为您不应将相同的id属性赋予多个元素。id属性在整个文档中必须是唯一的。如果不是,则只查找具有此id的第一个元素
尝试class=“notitle”
而不是id=“notitle”
,您的JS应该如下所示:
function notitle() {
var mylist=document.getElementsByClassName("notitle");
for (j=0; j<mylist.length; j++) {
var listitems= mylist[j].getElementsByTagName("a");
for (i=0; i<listitems.length; i++) {
listitems[i].removeAttribute("title");
}
}
}
您应该注意,并非所有浏览器/版本都支持document.getElementsByClassName。@Peter Kruithof:谢谢您的提示。我没有意识到这一点。谢谢,我尝试了类版本(在顶部更新)但是无法在最新的FF和Chrome中运行。@马丁:你把javascript改成了吗?所以它会寻找类名而不是id?是的,就像上面一样。Opera和IE也失败了。
function notitle() {
var mylist=document.getElementsByClassName("notitle");
for (j=0; j<mylist.length; j++) {
var listitems= mylist[j].getElementsByTagName("a");
for (i=0; i<listitems.length; i++) {
listitems[i].removeAttribute("title");
}
}
}
function notitle() {
$(".notitle a").removeAttr("title");
}