Javascript 修复imageswap onclick函数

我目前有一个工作图像交换代码。但我不想交换所有图像。如果您希望只能够彼此交换橙色图像。如果橙色图像与蓝色或红色图像交换，使橙色与红色或蓝色图像相同，而不影响红色或蓝色图像。这是一个样本

需要处理的代码

var pix = document.getElementById("GALLERY").getElementsByTagName("img");
for ( var p = 0; p < pix.length; ++p )
{
pix[p].onclick = picclick;
}

var firstImage = null;
function picclick( )
{
// to cancel a swap, click on first image again:
if ( firstImage == this ) 
{
    this.className = "normal";
    firstImage = null;
    return;
}
// is this first image clicked on?
if ( firstImage == null )
{
    // yes
    firstImage = this;
    this.className = "highlighted";
    document.getElementById('search').value = "";
    return; // nothing more to do
}
// aha! second image clicked on, so do swap
firstImage.className = "normal";
var temp = this.src;
this.src = firstImage.src;
firstImage.src = temp;
firstImage = null;

};

var pix=document.getElementById（“GALLERY”）.getElementsByTagName（“img”）；
对于（var p=0；p

红色和蓝色也不能相互交换

到目前为止，我所尝试的：

---

我一直在尝试如果

1st\u image\u clicked=sall.png

然后

2nd\u image\u clicked=sall.png

或者如果

1st\u image\u clicked=0-1.png

和

2nd\u image\u clicked=sall.png

如果我理解正确，这就是你想要的：

function picclick() {
    // to cancel a swap, click on first image again:
    if (firstImage == this) {
        this.className = "normal";
        firstImage = null;
        return;
    }
    // is this first image clicked on?
    if (firstImage == null) {
        // yes
        firstImage = this;
        this.className = "highlighted";
        //document.getElementById('search').value = "";
        return; // nothing more to do
    }
    // aha! second image clicked on, so do swap
    firstImage.className = "normal";
    //check if its not blue and red
    if (!(firstImage.alt == 'sold' && this.alt == 'payed') && !(firstImage.alt == 'payed' && this.alt == 'sold')) {
        if (firstImage.alt == 'sold' || firstImage.alt == 'payed') {
            //if first is blue or red, change second
            this.src = firstImage.src;
            this.alt = firstImage.alt;
        } else if (this.alt == 'sold' || this.alt == 'payed') {
            //if second is blue or red, change first
            firstImage.src = this.src;
            firstImage.alt = this.alt;
        } else {
            //do swap
            var temp = this.src;
            var temp2 = this.alt;
            this.src = firstImage.src;
            this.alt = firstImage.alt;
            firstImage.src = temp;
            firstImage.alt = temp2;
        }
    }
    firstImage = null;
};

---

展示您的尝试，解释失败的原因，改进您的措辞或举例说明。考虑一下，我想我用这个例子尽可能清楚地说明了这一点。我不确定我需要什么。我一直在尝试如果

1st\u image\u clicked=sall.png

然后

2nd\u image\u clicked=sall.png

或者如果

1st\u image\u clicked=0-1.png

和

2nd\u image\u clicked=sall.png