javascript onclick事件在具有SQL驱动数据的Chrome中不起作用

选项

s不支持

onclick

。您应该使用

select

的

onchange

。该值可以存储在属性中，如

数据县

（

数据-

属性可用于存储元素上的数据）：

Hi，您能在问题中包含php生成的实际html输出吗？使复制和粘贴更容易，并能更快地获得帮助。什么类型的元素是

#distr

？以下是Chrome 1 Decemberrie-IF AUGUST-23 CT ABRUD-AB中输出的代码。。。谢谢，它成功了，只是活动应该是onChange而不是onSelect。只有一次改变起了作用。再次感谢。

<select id='city' name='city' > 
<?php
$dbcon = mysql_connect($host, $username, $password);
mysql_select_db($db_name,$dbcon) or die( "Unable to select database");
$city_query = "SELECT city,county FROM citycatalog order by city asc";
$city_res = mysql_query($city_query);
$city_num = mysql_num_rows($city_res);
$i=0;
while($i < $city_num){
$city_val = mysql_result($city_res,$i,'city');
$county_val = mysql_result($city_res,$i,'county');
echo "<option value=\"$city_val\" onClick=\"document.getElementById('county').value = '$county_val'\" >$city_val</option>";
$i++;
};
?>
</select>
<input type="text" id='county' name='county' />

<select id='city' name='city' onchange="document.getElementById('county').value = this.options[this.selectedIndex].getAttribute('data-county');"> 
<?php
$dbcon = mysql_connect($host, $username, $password);
mysql_select_db($db_name,$dbcon) or die( "Unable to select database");
$city_query = "SELECT city,county FROM citycatalog order by city asc";
$city_res = mysql_query($city_query);
$city_num = mysql_num_rows($city_res);
$i=0;
while($i < $city_num){
$city_val = mysql_result($city_res,$i,'city');
$county_val = mysql_result($city_res,$i,'county');
echo "<option value=\"$city_val\" data-county=\"$county_val\" >$city_val</option>";
$i++;
};
?>
</select>
<input type="text" id='county' name='county' />