Javascript 如何从数组中删除元素。这不管用
我声明一个数组,如下所示:Javascript 如何从数组中删除元素。这不管用,javascript,jquery,Javascript,Jquery,我声明一个数组,如下所示: var myArray= []; 然后我添加数字元素 myArray.push(myNumber); 当我调用myArray.toString()时,数组看起来是这样的 1,4,3,9 我正在尝试删除某些类似的元素 for(var i = myArray.length; i >= 0; i--) { if(myArray[i] === theNumberIwantToRemove) { //theNumberIwantToRemove ==4
var myArray= [];
然后我添加数字元素
myArray.push(myNumber);
当我调用myArray.toString()时,数组看起来是这样的
1,4,3,9
我正在尝试删除某些类似的元素
for(var i = myArray.length; i >= 0; i--) {
if(myArray[i] === theNumberIwantToRemove) { //theNumberIwantToRemove ==4
myArray.splice(i, 1);
}
}
但它不起作用。输出仍然不变
1,4,3,9
有人知道为什么或者如何正确地做吗?这个怎么样
var array = [1, 2, 3, 4, 5]
var removeItem = 3;
obj = jQuery.grep(obj, function(value) {
return value != removeItem;
});
结果:
[1, 2, 4, 5]
你的例子绝对没有错 这工作正常,并给出输出:[1,3,9]。在这里为您自己测试: 您将在控制台中看到这一点:
- [1,4,3,9]
- [1,3,9]
使用 使用 在 还有 在
否则,您的代码似乎没有任何问题。它应该工作得很好。我看没问题。您是在尝试删除所有“4”元素,还是仅删除该值的第一次或最后一次出现?
var myArray= [];
myArray.push(1,4,3,9);
console.log(myArray);
for(var i = myArray.length; i >= 0; i--) {
if(myArray[i] === 4) { //theNumberIwantToRemove ==4
myArray.splice(i, 1);
}
}
console.log(myArray);
var array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
theNumberIwantToRemove = 5,
position = array.indexOf(theNumberIwantToRemove);
if (position !== -1) {
array.splice(position, 1);
}
alert(array);
var array = [0, 1, 5, 2, 3, 4, 5, 6, 7, 5, 8, 9],
theNumberIwantToRemove = 5,
position = array.indexOf(theNumberIwantToRemove),
result = array.filter(function (element) {
return element !== theNumberIwantToRemove;
});
alert(result);
var array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
theNumberIwantToRemove = 5
position = $.inArray(theNumberIwantToRemove, array);
if (position !== -1) {
array.splice(position, 1);
}
alert(array);
var array = [0, 1, 5, 2, 3, 4, 5, 6, 7, 5, 8, 9],
theNumberIwantToRemove = 5,
position = array.indexOf(theNumberIwantToRemove),
result = $(array).filter(function (index, element) {
return element !== theNumberIwantToRemove;
}).toArray();
alert(result);
var array = [0, 1, 5, 2, 3, 4, 5, 6, 7, 5, 8, 9],
theNumberIwantToRemove = 5,
position = array.indexOf(theNumberIwantToRemove),
result = $.grep(array, function (element) {
return element !== theNumberIwantToRemove;
});
alert(result);