Javascript Redux thunk:等待异步函数分派
我正在创建一个React本机应用程序,并使用redux和redux thunk来实现我的API请求。我想知道如何等待我的操作被调度,并确保我的状态已在异步thunk逻辑中更新。如果我理解正确,Javascript Redux thunk:等待异步函数分派,javascript,reactjs,react-native,redux,redux-thunk,Javascript,Reactjs,React Native,Redux,Redux Thunk,我正在创建一个React本机应用程序,并使用redux和redux thunk来实现我的API请求。我想知道如何等待我的操作被调度,并确保我的状态已在异步thunk逻辑中更新。如果我理解正确,wait将等待thunk结束,但操作尚未调度。尽管如此,正如您在我的用法中所看到的,我需要修改状态以相应地继续代码的其余部分 操作/user.js export const tryLogin = ( email: string, password: string, sessionToken: s
wait
将等待thunk结束,但操作尚未调度。尽管如此,正如您在我的用法中所看到的,我需要修改状态以相应地继续代码的其余部分
操作/user.js
export const tryLogin = (
email: string,
password: string,
sessionToken: string = ''
): Function => async (dispatch: Function) => {
const logUser = () => ({ type: LOG_USER })
const logUserSuccess = (data: any, infos: any) => ({
type: LOG_USER_SUCCESS,
data,
infos,
})
const logUserError = (signinErrorMsg: string) => ({
type: LOG_USER_ERROR,
signinErrorMsg,
})
dispatch(logUser())
try {
{ /* Some API requests via axios */ }
dispatch(logUserSuccess(responseJson, infos))
return true
} catch (error) {
{ /* Error handling code */ }
dispatch(logUserError(error.response.data.error))
return false
}
reducers/user.js
case LOG_USER:
return {
...state,
isLoggingIn: true,
}
case LOG_USER_SUCCESS:
return {
...state,
isLoggingIn: false,
data: action.data,
infos: action.infos,
error: false,
signinErrorMsg: '',
}
case LOG_USER_ERROR:
return {
...state,
isLoggingIn: false,
error: true,
signinErrorMsg: action.signinErrorMsg,
}
if (await trySignup(
emailValue,
firstNameValue,
lastNameValue,
passwordValue,
birthdateValue,
genderValue
)
) {
if (userReducer.data) {
navigation.navigate('Secured')
}
class RegisterScreen extends React.Component{
...
componentDidUpdate(prevProps) {
if (prevProps.signUpSuccess !== this.props.signUpSuccess){
if (this.props.signUpSuccess) {
navigation.navigate('Secured')
}
}
}
...
}
const mapStateToProps = (state) => ({
signUpSuccess: state.userReducer.signUpSuccess,
});
export default connect(mapStateToProps)(RegisterScreen);
RegisterScreen.js
case LOG_USER:
return {
...state,
isLoggingIn: true,
}
case LOG_USER_SUCCESS:
return {
...state,
isLoggingIn: false,
data: action.data,
infos: action.infos,
error: false,
signinErrorMsg: '',
}
case LOG_USER_ERROR:
return {
...state,
isLoggingIn: false,
error: true,
signinErrorMsg: action.signinErrorMsg,
}
if (await trySignup(
emailValue,
firstNameValue,
lastNameValue,
passwordValue,
birthdateValue,
genderValue
)
) {
if (userReducer.data) {
navigation.navigate('Secured')
}
class RegisterScreen extends React.Component{
...
componentDidUpdate(prevProps) {
if (prevProps.signUpSuccess !== this.props.signUpSuccess){
if (this.props.signUpSuccess) {
navigation.navigate('Secured')
}
}
}
...
}
const mapStateToProps = (state) => ({
signUpSuccess: state.userReducer.signUpSuccess,
});
export default connect(mapStateToProps)(RegisterScreen);
在Redux,
当一个动作被分派到商店时,它将用新的道具自动更新UI的状态
您可以在reducersignUpSuccess
中添加类似于isloggin
标志的标志,而不是查看已调度的操作,并侦听componentdiddupdate
生命周期方法中的更改
trySignup
可以单独调用(如在事件中、表单提交、按钮单击等)
RegisterScreen.js
case LOG_USER:
return {
...state,
isLoggingIn: true,
}
case LOG_USER_SUCCESS:
return {
...state,
isLoggingIn: false,
data: action.data,
infos: action.infos,
error: false,
signinErrorMsg: '',
}
case LOG_USER_ERROR:
return {
...state,
isLoggingIn: false,
error: true,
signinErrorMsg: action.signinErrorMsg,
}
if (await trySignup(
emailValue,
firstNameValue,
lastNameValue,
passwordValue,
birthdateValue,
genderValue
)
) {
if (userReducer.data) {
navigation.navigate('Secured')
}
class RegisterScreen extends React.Component{
...
componentDidUpdate(prevProps) {
if (prevProps.signUpSuccess !== this.props.signUpSuccess){
if (this.props.signUpSuccess) {
navigation.navigate('Secured')
}
}
}
...
}
const mapStateToProps = (state) => ({
signUpSuccess: state.userReducer.signUpSuccess,
});
export default connect(mapStateToProps)(RegisterScreen);
如果我理解正确,wait将等待thunk的结束
但该行动尚未发出
- 如果道具发生任何更改,可以更新渲染,所以在渲染方法中提取道具,并根据道具的更改更新UX
- 我建议你用它来检查你的行为 和当前保存的状态