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Javascript 未捕获类型错误:无法读取属性';提交';空的_Javascript_Forms - Fatal编程技术网

Javascript 未捕获类型错误:无法读取属性';提交';空的

Javascript 未捕获类型错误:无法读取属性';提交';空的,javascript,forms,Javascript,Forms,我试图用Javascript在php中调用表单,但出于某种原因 document.getElementById("form1").submit() 当它应该返回form1时返回null Javascript: <script> function verificar(){ ........ if(certoCarga && certoKm) document.getElementById("form1"

我试图用Javascript在php中调用表单,但出于某种原因

document.getElementById("form1").submit() 
当它应该返回form1时返回null

Javascript:

<script>
    function verificar(){
        ........
        if(certoCarga && certoKm)
            document.getElementById("form1").submit();
    }
</script>

功能验证卡(){
........
if(certoCarga&&certoKm)
document.getElementById(“form1”).submit();
}
Php:


....

如果当前放置在HEAD标记中的脚本标记代码听起来像是一个已准备就绪的问题,则可以将脚本标记代码放在body标记的结尾上方<代码>$(文档).ready(函数(){…
    <div id="quadro">
       <form id="form1" name="form1" method="post" action="alteraAuxController.php">
            ....
            <div id="rodape" align="center">
                    <input type="hidden" value="altera" name ="post1">
                    <input type="button" name="alterar" id="btn2" value="Alterar" onclick="verificar()">
            </div>
       </form>
   </div>