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Javascript React native:如何将参数传递给手势响应器回调_Javascript_Reactjs_React Native_React Native Listview - Fatal编程技术网

Javascript React native:如何将参数传递给手势响应器回调

Javascript React native:如何将参数传递给手势响应器回调,javascript,reactjs,react-native,react-native-listview,Javascript,Reactjs,React Native,React Native Listview,我有一个列表视图,其中的行由以下人员呈现: <ListView dataSource={_this.state.dataSource} renderRow={_this.renderPost} renderPost(post) { return ( <View ref="thisRowView" style={[MainList_styles.post]} onResponderMove={thi

我有一个列表视图,其中的行由以下人员呈现:

   <ListView
    dataSource={_this.state.dataSource}
    renderRow={_this.renderPost}

    renderPost(post) {
      return (
      <View ref="thisRowView"
        style={[MainList_styles.post]}
        onResponderMove={this.setPosition}
        onResponderRelease={this.resetPosition}
        onStartShouldSetResponder={this._onStartShouldSetResponder}
        onMoveShouldSetResponder={this._onMoveShouldSetResponder}
       > 
  ........
  resetPosition: function(var) {

我在回叫中得到了帖子,但是没有得到e,这是一个事件。如何实现这两种功能?

您可以通过在其参数中添加事件来修改方法:

onResponderRelease={(e) => this.resetPosition(e, post)}

你可以试试这个
onResponderRelease={(e)=>\u this.resetPosition(e,post)}
onResponderRelease={(e) => this.resetPosition(e, post)}