节点/JavaScript中的条件语句-超出调用堆栈大小

只要JSON的

type

字段中返回

music

值，我的脚本就会重新启动/发送

GET

请求

预期行为：运行GET调用，只要它返回

type==“music”

，但仍有一些运行以超过

最大调用堆栈大小而结束

如何克服这个问题

JSON结构：

{
  activity: "Solve a Rubik's cube",
  type: 'recreational',
  participants: 1,
  price: 0,
  link: '',
  key: '4151544',
  accessibility: 0.1
}

代码：

我认为在
while
关键字之后的条件下运行的代码无法访问
do
块中的变量声明
apirresulttype
。如果我没有弄错您的问题，您需要做的是在循环的正上方声明变量
apirresulttype
，并在进入循环后更新该变量。这样，do块和while条件都可以通过闭包访问变量

//import components
const https = require("https");
const options = new URL("https://www.boredapi.com/api/activity");

//obtain data using GET
//loop till get data where type = 'music'

https
  .get(options, (response) => {
    //console.log('statusCode:', response.statusCode);
    //console.log('headers:', response.headers);

    // declaration happens outside of do block. 
    let apiResultType;
    do {
      response.on("data", (data) => {
        //process.stdout.write(data);
        let apiResult = JSON.parse(data);

        // update the variable here, instead of initializing it. This block
        // has access to the outer blocks' variables
        apiResultType = apiResult.type;
        console.log(apiResult);
      });
    } while (apiResultType == "music"); //error: apiResultType is not defined
  })

  .on("error", (error) => {
    console.error(error);
  });


我不确定这是如何抛出错误的，因为您拥有的是有效代码。一旦条件计算为false，
do/while
循环结束，undefined不等于music的值。好的，我看到可变范围的东西在错误的位置。但是，代码可以工作，但返回JSON，其中
类型
与
音乐
不同。只要我得到
type==“music”
//import components
const https = require("https");
const options = new URL("https://www.boredapi.com/api/activity");

//obtain data using GET
//loop till get data where type = 'music'

https
  .get(options, (response) => {
    //console.log('statusCode:', response.statusCode);
    //console.log('headers:', response.headers);

    // declaration happens outside of do block. 
    let apiResultType;
    do {
      response.on("data", (data) => {
        //process.stdout.write(data);
        let apiResult = JSON.parse(data);

        // update the variable here, instead of initializing it. This block
        // has access to the outer blocks' variables
        apiResultType = apiResult.type;
        console.log(apiResult);
      });
    } while (apiResultType == "music"); //error: apiResultType is not defined
  })

  .on("error", (error) => {
    console.error(error);
  });