PHP/Javascript-在while循环中从mysql数据库在google地图上显示标记
我有一个while循环,它显示我数据库中的数据,如姓名地址等。我希望谷歌地图能够循环显示数据库中的地址。目前,谷歌地图只显示一次,我不认为它的循环与地图旁边列出的地址相同PHP/Javascript-在while循环中从mysql数据库在google地图上显示标记,javascript,php,google-maps,google-maps-api-3,Javascript,Php,Google Maps,Google Maps Api 3,我有一个while循环,它显示我数据库中的数据,如姓名地址等。我希望谷歌地图能够循环显示数据库中的地址。目前,谷歌地图只显示一次,我不认为它的循环与地图旁边列出的地址相同 <script src="https://maps.google.com/maps/api/js?key=[KEY-HERE]&signed_in=true&callback=initMap"async defer></script> while ($row = mysql_fetch
<script src="https://maps.google.com/maps/api/js?key=[KEY-HERE]&signed_in=true&callback=initMap"async defer></script>
while ($row = mysql_fetch_assoc($query)) {
echo "<div class='result-container'>
<div class='result-wrap'>
<div class='leftbox'>
<div class='titlebox'>
<h2>" . $row['company_name'] . "</h2>
</div>
<div class='box'>
" . ((empty($row['address_1'])) ? '' : "<strong> Address: </strong>" . $row['address_1']) . ((empty($row['address_2'])) ? '' : ", " . $row['address_2']) . ((empty($row['town'])) ? '' : ", " . $row['town']) . ((empty($row['county'])) ? '' : ", " . $row['county']) . ((empty($row['postcode'])) ? '' : ", " . $row['postcode']) . "
</div>
<div class='box'>
" . ((empty($row['tel'])) ? '' : "<strong> Telephone: </strong>" . $row['tel']) . ((empty($row['mobile'])) ? '' : "<strong> Mobile: </strong>" . $row['mobile']) . "
</div>
</div>
<div class='rightbox'>
<div class='service-pic'>
<img src='img/buddy.png' class='hvr-bob'>
</div>
<div id='map' style='width: 250px; height: 250px;'></div>
</div>
</div><br/>";
}
<script>
var address = "$row['address_1'], $row['town'], $row['postcode'], UK";
var map = new google.maps.Map(document.getElementById('map'), {
mapTypeId: google.maps.MapTypeId.TERRAIN,
zoom: 6
});
var geocoder = new google.maps.Geocoder();
geocoder.geocode({
'address': address
},
function(results, status) {
if(status == google.maps.GeocoderStatus.OK) {
new google.maps.Marker({
position: results[0].geometry.location,
map: map
});
map.setCenter(results[0].geometry.location);
}
});
</script>
while($row=mysql\u fetch\u assoc($query)){
回声“
“$row[‘公司名称’]”
“((空($row['address\u 1']))?”(地址:“$row['address\u 1'])。((空($row['address\u 2']))?”,$row['address\u 2'])。((空($row['town']),$row['town.)。((空($row['county']))?”,“,$row['county'])。((空($row['county']))),“,$row['county'])。((空($row['postcode.))),“)。”
“((空($row['tel'])?”:“电话:”。$row['tel'])。((空($row['mobile'])?”:“移动:”。$row['mobile'])”
“;
}
var address=“$row['address_1'],$row['town'],$row['postcode'],英国”;
var map=new google.maps.map(document.getElementById('map'),{
mapTypeId:google.maps.mapTypeId.TERRAIN,
缩放:6
});
var geocoder=new google.maps.geocoder();
地理编码({
“地址”:地址
},
功能(结果、状态){
if(status==google.maps.GeocoderStatus.OK){
新的google.maps.Marker({
位置:结果[0]。geometry.location,
地图:地图
});
map.setCenter(结果[0].geometry.location);
}
});
如果我正确理解了问题,您需要在页面上创建地图的多个实例
必须为脚本标记中指定为回调的initMap()
JavaScript函数生成代码。此函数将创建映射的多个实例,为此,我们可以引入$counter
变量,以确保我们确实有不同的实例。此外,我还从脚本标记中删除了一个signed_-in参数,因为它最近被弃用了
代码片段如下所示:
<script src="https://maps.google.com/maps/api/js?key=[KEY-HERE]&callback=initMap" async defer></script>
<?php
$counter = 0;
$jsInitFunction = "function initMap() { var geocoder = new google.maps.Geocoder(); ";
while ($row = mysql_fetch_assoc($query)) {
echo "<div class='result-container'>
<div class='result-wrap'>
<div class='leftbox'>
<div class='titlebox'>
<h2>" . $row['company_name'] . "</h2>
</div>
<div class='box'>
" . ((empty($row['address_1'])) ? '' : "<strong> Address: </strong>" . $row['address_1']) . ((empty($row['address_2'])) ? '' : ", " . $row['address_2']) . ((empty($row['town'])) ? '' : ", " . $row['town']) . ((empty($row['county'])) ? '' : ", " . $row['county']) . ((empty($row['postcode'])) ? '' : ", " . $row['postcode']) . "
</div>
<div class='box'>
" . ((empty($row['tel'])) ? '' : "<strong> Telephone: </strong>" . $row['tel']) . ((empty($row['mobile'])) ? '' : "<strong> Mobile: </strong>" . $row['mobile']) . "
</div>
</div>
<div class='rightbox'>
<div class='service-pic'>
<img src='img/buddy.png' class='hvr-bob'>
</div>
<div id='map" . $counter . "' style='width: 250px; height: 250px;'></div>
</div>
</div><br/>";
$jsInitFunction .= "var address" . $counter . " = '" . $row['address_1'] . "," . $row['town'] . "," . $row['postcode'] .", UK';
var map" . $counter . " = new google.maps.Map(document.getElementById('map" . $counter . "'), {
mapTypeId: google.maps.MapTypeId.TERRAIN,
zoom: 6
});
geocoder.geocode({
'address': address" . $counter . "
}, function(results, status) {
if(status == google.maps.GeocoderStatus.OK) {
new google.maps.Marker({
position: results[0].geometry.location,
map: map" . $counter . "
});
map" . $counter . ".setCenter(results[0].geometry.location);
}
});";
$counter++;
}
$jsInitFunction .= "}";
?>
<script>
<?php print $jsInitFunction; ?>
</script>
您正在javascript中打印php变量,但在var address
@AlbertAkki处没有php标记。我如何更正此问题?请尝试var address=“,,UK”@AlbertAkki我试过了,谷歌地图在while循环中只显示一次。你能在pastebin中粘贴你的浏览器源代码(CTRL+U)吗?这样它就能更好地理解到底是什么问题。如果有任何错误,请发布控制台错误谢谢,我会试试这个。我已经实现了代码,但我似乎遇到了500个错误,似乎不明白为什么我发布了完整的代码。请看第131-133行。不应该}
呆在
里面吗?我已经纠正了那个错误,但是我仍然得到了同样的错误。肯定是另一个问题,我已经更新了代码。好的。当
循环时关闭,当
循环时关闭位于之前的。如果(isset($\u GET['k'],$\u GET['t']){
似乎未关闭,那么关闭怎么样。