在JavaScript中使用XMLHttpRequest加载音频

在JavaScript中使用XMLHttpRequest加载音频,javascript,xmlhttprequest,web-audio-api,Javascript,Xmlhttprequest,Web Audio Api,我正在学习网络音频API。我在用JavaScript加载声音文件时遇到问题。请帮忙。这是我的密码 var source; function start() { console.log("WELCOME!!"); try{ var actx = new AudioContext(); }catch(e){ console.log('WebAudio api is not supported!!'); } source = actx.createBufferS

我正在学习网络音频API。我在用JavaScript加载声音文件时遇到问题。请帮忙。这是我的密码

var source;

function start() {
  console.log("WELCOME!!");
  try{
    var actx = new AudioContext();
  }catch(e){
    console.log('WebAudio api is not supported!!');
  }

  source = actx.createBufferSource()

  var req  = new XMLHttpRequest();
  req.open('GET','src3.ogg',true);
  req.responseType='ArrayBuffer';

  req.onload = function(){
    var audioData = req.response;
    actx.decodeAudioData(audioData,function(buffer){
      source.buffer = buffer;
      source.connect(actx.destination);
      source.loop();
    },
    function(e){
      console.log('Error in decoding audio'+e.err);
    }

  );
  }
  req.send();
}

function play() {
  source.start(0);
}
function stop(){
  source.stop(0);
}
浏览器显示此错误,如下所示:

XML Parsing Error: not well-formed
Location: file:///home/uzumaki/Web_Audio_Projects/src3.ogg
Line Number 1, Column 5:
并在body标记的onload事件上调用start()方法

req.responseType = "arraybuffer";
为了


未通过
XMLHttpResponse
instance

转换为小写。您是在Chrome还是Chrome上尝试代码?它在FireFox中。。。
req.responseType = "ArrayBuffer";