如何用Javascript包装异步调用?

如何用Javascript包装异步调用?,javascript,asynchronous,Javascript,Asynchronous,我希望有三个函数可以执行类似的操作: function getuser1(){ var user = b(); //do some stuff to user return user; } function getuser2(){ var user = asyncfinduser(); //do some different stuff to user return user; } function asyncfinduser(){ userDB.find( {

我希望有三个函数可以执行类似的操作:

function getuser1(){
  var user = b();
  //do some stuff to user
  return user;
}

function getuser2(){
  var user = asyncfinduser();
  //do some different stuff to user
  return user;
}

function asyncfinduser(){
  userDB.find( { /* some criteria */ }, function (error, user) {
    //return found user to functions above
    return user;
  });
)
显然,上述方法行不通,因此如何解决此问题?谢谢

由于您不能,您需要使用回调:

function getuser1(callback) {
  asyncfinduser(function(error, user) {
    if (error) return callback(error);
    //do some stuff to user
    callback(null, user);
  });
}

function getuser2(callback) {
  asyncfinduser(function(error, user) {
    if (error) return callback(error);
    //do some different stuff to user
    callback(null, user);
  });
}

function asyncfinduser(callback) {
  userDB.find( { /* some criteria */ }, function (error, user) {
    if (error) return callback(error);
    //return found user to functions above
    callback(null, user);
  });
}
但是,您可能可以应用:


您不应该将用户从异步函数返回到其他函数,而应该将其他函数作为回调传递给异步函数。正如@jahroy建议的那样,使用回调,或者从asyncfinduser函数返回承诺。
var Promise = …; // some library

function getuser1() {
  return asyncfinduser().then(function(user) {
    //do some stuff to user
    return user;
  });
}

function getuser2() {
  return asyncfinduser().then(function(user) {
    //do some different stuff to user
    return user;
  });
}

function asyncfinduser() {
  return new Promise(function(resolve, reject) {
    userDB.find( { /* some criteria */ }, function (error, user) {
    if (error) reject(error);
    else resolve(user); //return found user to functions above
  });
}