Javascript 在Spring/jQuery中更改JSON
我在春天创建了一个webapp,我遇到了一个对我来说非常困难的问题。在我的控制器中,我有以下方法:Javascript 在Spring/jQuery中更改JSON,javascript,jquery,arrays,json,mustache,Javascript,Jquery,Arrays,Json,Mustache,我在春天创建了一个webapp,我遇到了一个对我来说非常困难的问题。在我的控制器中,我有以下方法: @RequestMapping(value=“/add”,method=RequestMethod.POST) public@ResponseBody List addNewWord(@RequestBody Word,Principal){ addNewWord(word,principal.getName()); 返回getCurrentWords(principal.getName());
@RequestMapping(value=“/add”,method=RequestMethod.POST)
public@ResponseBody List addNewWord(@RequestBody Word,Principal){
addNewWord(word,principal.getName());
返回getCurrentWords(principal.getName());
}
受保护列表getCurrentWords(字符串用户名){
List accountWords=new ArrayList();
accountWords.addAll(wordService.listUserWords(username));
返回单词;
}
返回如下结构的JSON对象[这是一个示例]:
[
{"word":"battle","wordId":165},
{"word":"better","wordId":161},
{"word":"bread","wordId":167},
{"word":"cool","wordId":158},
{"word":"fight","wordId":166},
{"word":"forest","wordId":163},
{"word":"list","wordId":160},
{"word":"roll","wordId":164},
{"word":"semicolon","wordId":168},
{"word":"super","wordId":139},
{"word":"thing","wordId":162},
{"word":"word","wordId":159}
]
在我的jquery文件中,我有一个代码:
$("#add_word_submit").click(function(e) {
e.preventDefault();
$("#add_word_input").focus();
var word = $('#add_word').serializeObject();
$.postJSON("words/add.html", word, function(words) {
$("#add_word_input").val("");
showDividedAccountWords(words);
});
});
function showDividedAccountWords(words) {
var accountWords = new Object();
accountWords.words = words;
wordListTemplate =
"{{#words}}" +
"<ul class='word_list'>" +
"<li class='word'>" +
"<strong>{{wordId}}: </strong>" +
"<span>{{word}}</span>" +
"</li>" +
"</ul>";
"{{/words}}" +
var accountWordsHTML = Mustache.to_html(wordListTemplate, accountWords);
$("#words").html(accountWordsHTML);
}
$(“添加单词”和“提交”)。单击(功能(e){
e、 预防默认值();
$(“添加单词输入”).focus();
var word=$('#add_word').serializeObject();
$.postJSON(“words/add.html”、word、函数(words){
$(“#添加#单词#输入”).val(“”);
显示dividedaccountwords(单词);
});
});
函数showDividedAccountWords(单词){
var accountWords=新对象();
accountWords.words=单词;
wordListTemplate=
“{{{单词}”+
“”+
“- ”+
“{{wordId}:”+
“{{word}}”+
“
”+
“
”;
“{{/words}}”+
var accountWordsHTML=Mustache.to_html(wordlistmplate,accountWords);
$(“#words”).html(accountWordsHTML);
}
当我通过单击#add_word_submit提交表单时,jquery将JSON对象[new word object]发送到Spring控制器,而Spring控制器将获得当前用户单词列表。当前单词列表作为JSON对象返回[我在上面粘贴了它],接下来它将用于我的mustache.js模板中
一般来说,我希望在添加新词时,thorugh ajax自动刷新用户单词列表。到目前为止,一切都是好的,工作得很好,但我希望有稍微不同的输出。现在我得到一份ul列表:
<ul class="word_list">
<li class="word"><span>1: Word</span></li> [1]
<li class="word"><span>1: Word</span></li> [2]
<li class="word"><span>1: Word</span></li> [3]
...
<li class="word"><span>1: Word</span></li> [13]
</ul>
- 1:word
[1]
- 1:word
[2]
- 1:word
[3]
...
- 1:word
[13]
但我希望有一个输出,当我通过JSON(如上所述)获得当前单词列表时,我希望将其划分为许多ul列表,其中最多只有10个单词。因此,如果我有上面[13个单词]这样的列表,我希望有一个10个单词的列表,下一个3个单词的列表,等等,当有更多的单词时
<ul class="word_list">
<li class="word"><span>1: Word</span></li> [1]
<li class="word"><span>1: Word</span></li> [2]
<li class="word"><span>1: Word</span></li> [3]
...
<li class="word"><span>1: Word</span></li> [10]
</ul>
<ul class="word_list">
<li class="word"><span>1: Word</span></li> [1]
<li class="word"><span>1: Word</span></li> [2]
<li class="word"><span>1: Word</span></li> [3]
</ul>
- 1:word
[1]
- 1:word
[2]
- 1:word
[3]
...
- 1:word
[10]
- 1:word
[1]
- 1:word
[2]
- 1:word
[3]
我不知道在哪里做这件事最好(在Controller中或者仅仅在jQuery中),以及如何做?我真的非常感谢你的帮助 试试这个:
function showDividedAccountWords(words) {
var wordListTemplate =
"{{#words}}" +
"<ul class='word_list'>" +
"<li class='word'>" +
"<strong>{{wordId}}: </strong>" +
"<span>{{word}}</span>" +
"</li>" +
"</ul>" +
"{{/words}}";
// Take 10 words at a time, until there are no words.
for(var w = words.splice(0, 10); w.length > 0; w = words.splice(0, 10)) {
var accountWordsHTML = Mustache.to_html(wordListTemplate, {words: w});
$("#words").append(accountWordsHTML);
}
函数showDividedAccountWords(words){
变量wordListTemplate=
“{{{单词}”+
“”+
“- ”+
“{{wordId}:”+
“{{word}}”+
“
”+
“
”+
“{{/字}}”;
//一次读10个单词,直到没有单词为止。
对于(var w=字.拼接(0,10);w.长度>0;w=字.拼接(0,10)){
var accountWordsHTML=Mustache.to_html(wordListTemplate,{words:w});
$(“#字”).append(accountWordsHTML);
}
这很有效!你真是太天才了:)。我没想到我的问题能这么快解决。非常感谢!Mariusz-第一个版本中有一个严重的错误。这是一个永无止境的循环。请切换到更新版本!Mariusz,我的第一个答案有一个严重的错误,一个永无止境的循环。请切换到我的更新答案!