Javascript LDAP JS，节点JS查找以字符串模式传递的用户

我目前正在Angular JS应用程序中使用LDAP JS进行身份验证，一切正常

我现在正在构建一个新视图，我的要求是：

• 我有一个文本框，管理员将在其中写入可能是LDAP中存在的用户id的几个字母
• 我想在typeahead/suggestions上显示LDAP中存在的应用程序匹配ID。我知道typeahead是如何工作的，所以这不是一个问题。问题是如何在

  search（）

  方法中为

  uid

  传递rejex或模式匹配之类的东西

我的示例代码如下：

function GetAllLDAPUser(dnFilter, res) {

    client.search('uid=**WHAT-PATTERN-CAN-I-PASS-HERE**' + dnFilter, opts, function(err, result) {

            result.on('searchEntry', function(entry) {

                // I usually read entry.object or entry.raw here , that works

            });
            result.on('end', function(result) {

                .......
            });
        }
    }
}

所以问题是我应该通过什么来代替

WHAT-PATTERN-CAN-I-PASS-HERE

结果:

---

假设我键入

an

。typeahead将显示所有以

an

开头的用户id，如

ana

、

anamon

、

analisa

等。

我已经编写了最终解决方案并关闭了

对于模式匹配，我们需要处理传递给搜索方法的option对象中的“filter”字段。所以我最后做了如下的事情：

var dnFilter = 'ou=People,o=Intra,dc=YOURCOMPANY,dc=com'; //depends on your LDAP settings.
var query;
var matchedUsers = [];
query.LDAPName = "dummy"; //some name which resides in LDAP 
//You can even have one simple variable rather than having this query object.
opts = {
    scope: 'sub',
    filter: (shcDisplayName = '+ query.LDAPName + ')
    '
};

//Do not use 'shcDisplayName' , this will be any variable stored in your LDAP object. You need get 
//the structure of LDAP end point you are working on. For me, I had one variable 'shcDisplayName'
//on which I wanted to play so I am using this variable in my filter.
client.search(dnFilter, opts, function(err, result) {

        result.on('searchEntry', function(entry) {
                matchedUsers.push({
                    'Name': entry.object.shcDisplayName,
                    'Id': entry.object.uid
                });
            }

            result.on('end', function(result) {

                    if (matchedUsers.length) { //if any match was found.

                        //send the json result back
                        res.json(matchedUsers);

                        //if you want to send json back, do not use res.send() otherwise you will end up getting
                        //circular reference error. 
                    }
                }

                result.on('error', function(ex) {
                    //Handle errors here if any
                });

            });
    }
}