Javascript SQLite向js中的现有值添加数值变量
我有下表Javascript SQLite向js中的现有值添加数值变量,javascript,sqlite,Javascript,Sqlite,我有下表 buildingcode buildingreceiptno buildingaddress buildingpay 1012 2 address 1 0 1001 3 address 2 0 1003 0 address 3 0 我想通过一个数值变量来更新某个构建代码的buildingreceive 我使
buildingcode buildingreceiptno buildingaddress buildingpay
1012 2 address 1 0
1001 3 address 2 0
1003 0 address 3 0
我想通过一个数值变量来更新某个构建代码的buildingreceive
我使用以下代码,但它不起作用
t.executeSql('UPDATE buildings SET buildingpay = ?, buildingreceiptno = buildingreceiptno + numericalValue WHERE buildingaddress = ?',
[myrow.payamount.toFixed(2), myrow.buildingaddress]);
myrow.payamount.toFixed(2)、myrow.buildingaddress是正确的变量您可以对其进行改进,但这应该是解决问题的有效方法:
db.transaction(function(tx) {
// Get buildingreceiptno value
tx.executeSql(
"SELECT buildingreceiptno FROM buildings WHERE buildingaddress = ?",
[myrow.buildingaddress],
function(tx, res) {
var buildingreceiptno = res.rows.item(0).buildingreceiptno;
tx.executeSql(
"UPDATE buildings SET buildingpay = ?, buildingreceiptno = ? WHERE buildingaddress = ?",
[myrow.payamount.toFixed(2), buildingreceiptno + numericalValue, myrow.buildingaddress],
function(tx, res) { console.log(tx, res); },
function(tx, err) { console.log('ERROR: ', tx, err); }
);
},
function(tx, err) { console.log('ERROR: ', tx, err); });
});
总是使用错误回调来打印错误,这很有帮助