Javascript 同级来自Dom规范：。。。但不是所有的子节点（例如，文本节点是原始元素的子元素的子元素）。它按顺序打印标签名。是否有方法按标记名出现的顺序打印标记名？我问了另外一个问题，我试过了。它按顺序打印标签名。是否有方法按标记名出现的顺序打印标记名？我在这里问了一个

---

同级来自Dom规范：。。。但不是所有的子节点（例如，文本节点是原始元素的子元素的子元素）。它按顺序打印标签名。是否有方法按标记名出现的顺序打印标记名？我问了另外一个问题，我试过了。它按顺序打印标签名。是否有方法按标记名出现的顺序打印标记名？我在这里问了一个单独的问题

$(elem)
  .contents()
  .filter(function() {
    return this.nodeType === 3; //Node.TEXT_NODE
  });

var getTextNodesIn = function(el) {
    return $(el).find(":not(iframe)").addBack().contents().filter(function() {
        return this.nodeType == 3;
    });
};

getTextNodesIn(el);

function getTextNodesIn(node, includeWhitespaceNodes) {
    var textNodes = [], nonWhitespaceMatcher = /\S/;

    function getTextNodes(node) {
        if (node.nodeType == 3) {
            if (includeWhitespaceNodes || nonWhitespaceMatcher.test(node.nodeValue)) {
                textNodes.push(node);
            }
        } else {
            for (var i = 0, len = node.childNodes.length; i < len; ++i) {
                getTextNodes(node.childNodes[i]);
            }
        }
    }

    getTextNodes(node);
    return textNodes;
}

getTextNodesIn(el);

$('selector').clone().children().remove().end().contents();

$('selector').clone().children().remove().end();

String.prototype.stripTags=function(){
var rtag=/<.*?[^>]>/g;
return this.replace(rtag,'');
}

var newText=$('selector').html().stripTags();

$.fn.nextNode = function(){
  var contents = $(this).parent().contents();
  return contents.get(contents.index(this)+1);
}

$('#my_id').nextNode();

$('body').find('*').contents().filter(function () { return this.nodeType === 3; });

var textContents = $(document.getElementById("ElementId").childNodes).filter(function(){
        return this.nodeType == 3;
});

jQuery("#resultTable td").content().wrap("<pre/>")

jQuery('body').descendants('all');

jQuery('body').descendants(true);

jQuery('body').descendants();

jQuery.fn.descendants = ( textNodes ) ->

    # if textNodes is 'all' then textNodes and elementNodes are allowed
    # if textNodes if true then only textNodes will be returned
    # if textNodes is not provided as an argument then only element nodes
    # will be returned

    allowedTypes = if textNodes is 'all' then [1,3] else if textNodes then [3] else [1]

    # nodes we find
    nodes = []


    dig = (node) ->

        # loop through children
        for child in node.childNodes

            # push child to collection if has allowed type
            nodes.push(child) if child.nodeType in allowedTypes

            # dig through child if has children
            dig child if child.childNodes.length


    # loop and dig through nodes in the current
    # jQuery object
    dig node for node in this


    # wrap with jQuery
    return jQuery(nodes)

var __indexOf=[].indexOf||function(e){for(var t=0,n=this.length;t<n;t++){if(t in this&&this[t]===e)return t}return-1}; /* indexOf polyfill ends here*/ jQuery.fn.descendants=function(e){var t,n,r,i,s,o;t=e==="all"?[1,3]:e?[3]:[1];i=[];n=function(e){var r,s,o,u,a,f;u=e.childNodes;f=[];for(s=0,o=u.length;s<o;s++){r=u[s];if(a=r.nodeType,__indexOf.call(t,a)>=0){i.push(r)}if(r.childNodes.length){f.push(n(r))}else{f.push(void 0)}}return f};for(s=0,o=this.length;s<o;s++){r=this[s];n(r)}return jQuery(i)}

$('element')
    .contents()
    .filter(function(){
        return this.nodeType === 3 && $.trim(this.nodeValue) !== '';
    });

$('element')
        .contents()
        .filter(function(){
            return this.nodeType === 3 && /\S/.test(this.nodeValue);
        });