Javascript 如何在sequelize中选择案例查询?
我有一个sql查询:Javascript 如何在sequelize中选择案例查询?,javascript,sql,node.js,postgresql,sequelize.js,Javascript,Sql,Node.js,Postgresql,Sequelize.js,我有一个sql查询: SELECT field1, field2, CASE WHEN field1=1 THEN 'a' ELSE 'b' END AS field3 FROM test 我想用sequelizejs实现它 const params = { attributes: //DO SELECT CASE, }; yield Model.findAll(params); 有人能帮我吗?谢谢。感谢那些仍在寻找答案的人 Model.findAll({
SELECT field1, field2,
CASE
WHEN field1=1 THEN 'a'
ELSE 'b'
END
AS field3
FROM test
我想用sequelizejs实现它
const params = {
attributes: //DO SELECT CASE,
};
yield Model.findAll(params);
有人能帮我吗?谢谢。感谢那些仍在寻找答案的人
Model.findAll({
attributes: [[models.sequelize.literal('CASE WHEN "field1" = true THEN 55 ELSE 23 END'), 'field3']]
}
或
因此,在我的示例中,当field1为true时,它将返回55,否则返回23。这将生成如下查询
SELECT CASE WHEN "field1" THEN 55 ELSE 23 END AS "field3" FROM "models"
有关更多信息,请参阅文档
SELECT CASE WHEN "field1" THEN 55 ELSE 23 END AS "field3" FROM "models"