Javascript 用于删除常用项的ES6阵列筛选器

我试图删除两个数组中常见的

slot\u id

，并构建一个没有重复的

slot\u id

的对象数组

尝试了以下操作，但其结果是另一个数组中的输出数组，即输出

[数组（0），数组（2）]

。我期待一个输出数组，如下所示

预期结果：

[{
  "_id": "5b55c44038a7701a93fb1a68",
  "end_time": {
    "hours": "01"
  },
  "start_time": {
    "hours": "00"
  }
}, {
  "_id": "5b55c44038a7701a93fb1a67",
  "end_time": {
    "hours": "03"
  },
  "start_time": {
    "hours": "01"
  }
}]

输入数组

Slots = [{
  "_id": "5b55c43532996fec4f500aa5",
  "time_slots": [{
    "_id": "5b55c43538a7701a93fb1a58",
    "end_time": {
      "hours": "01"
    },
    "start_time": {
      "hours": "00"
    }
  }, {
    "_id": "5b55c43538a7701a93fb1a57",
    "end_time": {
      "hours": "03"
    },
    "start_time": {
      "hours": "01"
    }
  }]
}, {
  "_id": "5b55c44032996fec4f500abf",
  "time_slots": [{
    "_id": "5b55c44038a7701a93fb1a68",
    "end_time": {
      "hours": "01"
    },
    "start_time": {
      "hours": "00"
    }
  }, {
    "_id": "5b55c44038a7701a93fb1a67",
    "end_time": {
      "hours": "03"
    },
    "start_time": {
      "hours": "01"
    }
  }]
}]

filterData = [{
  "slot_id": "5b55c43538a7701a93fb1a57",
  "user_id": "5b4dbbf9788bbb4fd01cea33"
}, {
  "slot_id": "5b55c43538a7701a93fb1a58",
  "user_id": "5b4dbbf9788bbb4fd01cea33"
}]

let result = Slots.map(m => m.time_slots.filter(e => !filterData.find(a => e._id == a.slot_id)));

使用concat数组

“时间”方面的时隙：“{”方面的意思是：“““{”方面的意思是：：“““{”方面的意思是：“{”方面的意思是：“{”的意思是：5B55C455C4353838A7701A701A701A701A701A79A79A79A797777777777A7766666666F4F4F555555FF55555555F444444FFF4FF555555A7777777777777710101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010101010时间：{“小时”：“01”}，“开始时间”：{“小时”：“00”}，{“id”：“5b55c44038a7701a93fb1a67”，“结束时间”：{“小时”：“03”}，“开始时间”：{“小时”：“01”}]； const filterData=[{“slot_id”：“5b55c43538a7701a93fb1a57”，“user_id”：“5B4DBF9788BBB4FD01CEA33”}，{“slot_id”：“5b55c43538a7701a93fb1a58”，“user_id”：“5B4DBF9788BBB4FD01CEA33”}； const result=Slots.map（m=>m.time\u Slots.filter（e=>！filterData.find（a=>e.。\u id==a.slot\u id）））.reduce（（累加器，currentValue）=>acculator.concat（currentValue））；

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document.write（''+JSON.stringify（result，null，'\t'）+''）是否要获取所有唯一插槽？是否可能重复检查上述问题的第一个答案