Javascript Django:语法错误：意外标记<；

我正在使用django和jquery来使用ajax上传文件。但是，在文件上传之后（并且文件确实正确上传；数据库更新并且它们在服务器上），javascript返回一个

SyntaxError:Unexpected token，根据文档，
form\u valid（）
方法需要以
HTTPResponse
的形式返回JSON。在超类上调用
form\u valid（）
将覆盖前两行上创建的响应

编辑-这对我有用：

def response_mimetype(request):
  if "application/json" in request.META['HTTP_ACCEPT']:
    return "application/json"
  else:
    return "text/plain"

class UploadedFileCreateView(CreateView):
  model = UploadedFile
  form_class = UploadedFileForm

  def form_valid(self, form):
    self.object = form.save(commit=False)
    self.object.project_id = self.kwargs['proj_key']
    self.object.save()
    f = self.request.FILES.get('file')

    data = [{
      'name': self.object.name(),
      'url': "/uploads/xmlfiles/" + self.object.name().replace(" ", "_"),
      'type': "application/xml",
      'size': self.object.file.size,
      'delete_url': reverse('fileupload:upload-delete',
        kwargs={'pk':self.object.id,
        'proj_key':self.kwargs['proj_key']}),
      'delete_type': "DELETE"}]

    return HttpResponse(simplejson.dumps(data), content_type = response_mimetype(self.request))

上面链接中的代码将ajax响应代码捆绑为一个Mixin，它将允许项目中的其他表单重用代码

在Firefox插件Firebug、Net选项卡或Chrome等价物中查看对Ajax调用的响应将有所帮助。这些将显示请求和响应标题，确保发送和返回正确的设置。
在Chrome中尝试，打开DevTools，并确保单击“源”选项卡上的“暂停未捕获异常”切换。这将帮助您定位错误，并有望进入调试的下一步。您正在创建
JSONResponse
实例，但不会从视图中返回它。您的JSON调用正在获取任何
super（UploadedFileCreateView，self）。form\u valid
返回-HTTP重定向，如果内存可用。始终查看从服务器返回的内容，使用控制台中的net选项卡。对于您的代码，我会将
空文件上载结果作为javascript错误，虽然控制台中似乎没有javascript异常。啊，好的，你能发布你的html/javascript吗？然后我很乐意正确地调试代码，；）。非常感谢！这是我的模板：这里引用了javascript:@Plasma我已经调试了一个来自github的克隆，我上面帖子中编辑的
form\u valid（）
正在为我使用firefox中的
jquery文件上传
插件。非常好看的项目，顺便说一句。这解决了我的问题。谢谢你多跑了一英里！
class UploadedFile(models.Model):
    """This represents a file that has been uploaded to the server."""
    STATE_UPLOADED = 0
    STATE_ANNOTATED = 1
    STATE_PROCESSING = 2
    STATE_PROCESSED = 4
    STATES = (
        (STATE_UPLOADED, "Uploaded"),
        (STATE_ANNOTATED, "Annotated"),
        (STATE_PROCESSING, "Processing"),
        (STATE_PROCESSED, "Processed"),
    )

    status = models.SmallIntegerField(choices=STATES,
        default=0, blank=True, null=True) 
    file = models.FileField(upload_to=settings.XML_ROOT)
    project = models.ForeignKey(Project)

    def __unicode__(self):
        return self.file.name

    def name(self):
        return os.path.basename(self.file.name)

    def save(self, *args, **kwargs):
        if not self.status:
            self.status = self.STATE_UPLOADED
        super(UploadedFile, self).save(*args, **kwargs)

    def delete(self, *args, **kwargs):
        os.remove(self.file.path)
        self.file.delete(False)
        super(UploadedFile, self).delete(*args, **kwargs)

    def get_absolute_url(self):
        return u'/upload/projects/%d' % self.id 

class UploadedFileForm(ModelForm):
    class Meta:
        model = UploadedFile
        exclude = ('project',)

def response_mimetype(request):
  if "application/json" in request.META['HTTP_ACCEPT']:
    return "application/json"
  else:
    return "text/plain"

class UploadedFileCreateView(CreateView):
  model = UploadedFile
  form_class = UploadedFileForm

  def form_valid(self, form):
    self.object = form.save(commit=False)
    self.object.project_id = self.kwargs['proj_key']
    self.object.save()
    f = self.request.FILES.get('file')

    data = [{
      'name': self.object.name(),
      'url': "/uploads/xmlfiles/" + self.object.name().replace(" ", "_"),
      'type': "application/xml",
      'size': self.object.file.size,
      'delete_url': reverse('fileupload:upload-delete',
        kwargs={'pk':self.object.id,
        'proj_key':self.kwargs['proj_key']}),
      'delete_type': "DELETE"}]

    return HttpResponse(simplejson.dumps(data), content_type = response_mimetype(self.request))