Javascript 我的唯一函数在阵列上不起作用？

我有一个函数，用于对给定数组进行排序/排序/uniqify

下面是一些代码： 气泡排序-

function sort(postsCollection, type, direction){
    let target = postsCollection[0][type];
    let swapp = false,
        n = postsCollection[0].length - 1,
        x = postsCollection[0];
    do {
        swapp = false;
        for(let i = 0; i < n; i++){
            if(x[i][type] < x[i+1][type]){
                x[i+1] = x[i];
                swapp = true;
            }
        }
        n--;
    } while (swapp);
    return x;
}

它应该使数据数组唯一。但事实并非如此

以下是一个示例：

{"posts":[{"author":"Rylee Paul","authorId":9,"id":1,"likes":960,"popularity":0.13,"reads":50361,"tags":["tech","health"]},{"author":"Zackery Turner","authorId":12,"id":2,"likes":469,"popularity":0.68,"reads":90406,"tags":["startups","tech","history"]},{"author":"Zackery Turner","authorId":12,"id":2,"likes":469,"popularity":0.68,"reads":90406,"tags":["startups","tech","history"]},{"author":"Zackery Turner","authorId":12,"id":2,"likes":469,"popularity":0.68,"reads":90406,"tags":["startups","tech","history"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Elisha Friedman","authorId":8,"id":13,"likes":230,"popularity":0.31,"reads":64058,"tags":["design","tech"]},{"author":"Adalyn Blevins","authorId":11,"id":37,"likes":107,"popularity":0.55,"reads":35946,"tags":["tech","health","history"]},{"author":"Adalyn Blevins","authorId":11,"id":37,"likes":107,"popularity":0.55,"reads":35946,"tags":["tech","health","history"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Jon Abbott","authorId":4,"id":46,"likes":89,"popularity":0.96,"reads":79298,"tags":["culture","tech"]},{"author":"Bryson Bowers","authorId":6,"id":85,"likes":25,"popularity":0.18,"reads":16861,"tags":["tech"]},{"author":"Bryson Bowers","authorId":6,"id":85,"likes":25,"popularity":0.18,"reads":16861,"tags":["tech"]},{"author":"Bryson Bowers","authorId":6,"id":85,"likes":25,"popularity":0.18,"reads":16861,"tags":["tech"]},{"author":"Bryson Bowers","authorId":6,"id":85,"likes":25,"popularity":0.18,"reads":16861,"tags":["tech"]},{"author":"Bryson Bowers","authorId":6,"id":85,"likes":25,"popularity":0.18,"reads":16861,"tags":["tech"]}]}

---

为什么这个数组不是唯一的？是什么给出了上述结果？

您假设

[…新集合（数据）]

将过滤掉重复的值–这基本上是正确的–但是：

Set

s只过滤掉重复的（字符串、数字、布尔值等）。即使对象具有完全相同的内容，也不认为它们彼此相等✝.

您可以调用自己的

uniqueFilter（postsCollection）

函数，而不是使用

[…new Set（postsCollection）]

，该函数根据对象内容的相同性过滤对象（请参阅）

---

✝ 只有当对象在字面上是对同一对象的引用时，才认为它们彼此“相等”。e、 g

const a = {};
a === {}; // false

const b = a;
a === b; // true (because `b` is literally pointing to the exact same object as `a`)

---

将您创建的每个对象都视为具有一个始终使其唯一的密钥，而不管其内容如何。

我最近发现，

[…新集合（arr）]

不会删除对象，因为它们被视为object:object

const a = {};
a === {}; // false

const b = a;
a === b; // true (because `b` is literally pointing to the exact same object as `a`)