Javascript，一个带有回调处理程序的对象，如何将其重写为wait/async样式？

我使用了一个api，它的对象提供回调处理程序，一个搜索函数

function searchAndDoSomething(name){
    let searchObj = new APIobj(para1,{onSearchComplete:searchCompleteHandler});
    searchObj.search(name);
}
function searchCompleteHandler(result){
    doSomething(result);
}

Async Main(){
      result = await searchAndDoSomething(name);
      searchCompleteHandler(result);  
}

async Main() { // Note it's `async`, not `Async`
    const result = await searchAndDoSomething(name); // note declaration
    searchCompleteHandler(result);  
}

我的目标是这样做：

function searchAndDoSomething(name){
    let searchObj = new APIobj(para1,{onSearchComplete:searchCompleteHandler});
    searchObj.search(name);
}
function searchCompleteHandler(result){
    doSomething(result);
}

Async Main(){
      result = await searchAndDoSomething(name);
      searchCompleteHandler(result);  
}

async Main() { // Note it's `async`, not `Async`
    const result = await searchAndDoSomething(name); // note declaration
    searchCompleteHandler(result);  
}

但是如何重写searchAndDoSomething呢

async searchAndDoSomething(name){
     return new Promise(function(resolve){
         let searchObj = new APIobj(para1,{onSearchComplete:resolve};//this will call a resolve function.
     //and
     resolve(name);//instead of searchObj.search will no effect too.
    })
}

---

您的尝试已接近尾声，但由于您需要显式地创建承诺（因为

APIobj

没有），因此您的函数没有理由是

async

。此外，您只需调用

resolve

一次：

searchAndDoSomething(name) {
    return new Promise((resolve) => {
        const searchObj = new APIobj(para1, {onSearchComplete: resolve});
        searchObj.search(name);
    });
}

大概有一种方法可以让APIobj发出故障信号；如果是这样，您需要调用

拒绝

。例如，如果我猜测一个名为

onSearchError

的回调：

searchAndDoSomething(name) {
    return new Promise((resolve, reject) => {
        const searchObj = new APIobj(para1, {
            onSearchComplete: resolve,
            onSearchError: reject
        });
        searchObj.search(name);
    });
}

然后，您可以这样使用：

function searchAndDoSomething(name){
    let searchObj = new APIobj(para1,{onSearchComplete:searchCompleteHandler});
    searchObj.search(name);
}
function searchCompleteHandler(result){
    doSomething(result);
}

Async Main(){
      result = await searchAndDoSomething(name);
      searchCompleteHandler(result);  
}

async Main() { // Note it's `async`, not `Async`
    const result = await searchAndDoSomething(name); // note declaration
    searchCompleteHandler(result);  
}

或

---

APIobj

是否无法发出失败的信号？我查阅了说明，似乎搜索结果对象没有我认为您的评论在那里被截断了…我查阅了说明，似乎搜索“结果”对象没有失败的类型，也许我不知道失败的位置。所以我屏蔽了我的WiFi，看到控制台弹出一个GET错误。以0（）结尾。感谢@Bergi，一如既往的敏锐目光！