javascript通过关键字和don'；如果用括号括起来，则不能拆分

我有以下输入字符串：

关键字=>和/或

let query = `(Application = http AND "Server Port" "Not In" 80,443,8080) 
              AND "Client Port" Between 22,33 
              OR ("File Size" In 220,400,500 AND "File Size" "Not In" 5,10,60)
              OR "Client IP" != 1.0.2.1 
              OR Application = skype`;

//I want split the above string into following format

[
  '(Application = http AND "Server Port" "Not In" 80,443,8080)', 
  'AND',
  '"Client Port" Between 22,33',
  'OR'
  '("File Size" In 220,400,500 AND "File Size" "Not In" 5,10,60)'
  'OR'
  '"Client IP" != 1.0.2.1'
  'OR',
  'Application = skype'
]

我有下面的代码，或者用关键字分割字符串，或者如果字符串完全用括号括起来

 query.split(/AND|OR/g); //Split based on key words

************
 var str = '((Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25)) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)';

 var final = str.replace(/\((?!\()/g,"['")        //replace ( with [' if it's not preceded with (
           .replace(/\(/g,"[")               //replace ( with [
           .replace(/\)/g,"']")              //replace ) with '] 
           .replace(/\sAND\s/g,"','AND','")  //replace AND with ','AND','
           .replace(/\sOR\s/g,"','OR','")    //replace OR with ','OR','
           .replace(/'\[/g,"[")              //replace '[ with [
           .replace(/\]'/g,"]")              //replace ]' with ]
           .replace(/"/g,"\\\"")             //escape double quotes
           .replace(/'/g,"\"");              //replace ' with "
console.log(JSON.parse("["+final+"]"))

---

忽略括号拆分字符串有什么帮助吗？基本上，我想提取任何内容（+关键字），包括括号。

您可以使用以下正则表达式：

 query.split(/AND|OR/g); //Split based on key words

************
 var str = '((Application = smtp AND "Server Port" != 25) AND (Application = smtp AND "Server Port" != 25)) OR (Application = pop3 AND "Server Port" != 110) OR (Application = imap AND "Server Port" != 143) AND (Application = imap OR "Server Port" != 143)';

 var final = str.replace(/\((?!\()/g,"['")        //replace ( with [' if it's not preceded with (
           .replace(/\(/g,"[")               //replace ( with [
           .replace(/\)/g,"']")              //replace ) with '] 
           .replace(/\sAND\s/g,"','AND','")  //replace AND with ','AND','
           .replace(/\sOR\s/g,"','OR','")    //replace OR with ','OR','
           .replace(/'\[/g,"[")              //replace '[ with [
           .replace(/\]'/g,"]")              //replace ]' with ]
           .replace(/"/g,"\\\"")             //escape double quotes
           .replace(/'/g,"\"");              //replace ' with "
console.log(JSON.parse("["+final+"]"))

query.split(/(AND|OR)(?![^(]*\))/);

这将只匹配一个

和

或一个

或

，如果后面没有

）

且前面没有

（

）的话。这是通过“负面展望”完成的：

（？！）

通过对空格（

\s*

）进行一些修剪，您可以得到以下结果：

var str='（（应用程序=smtp和“服务器端口”！=25）和（应用程序=smtp和“服务器端口”！=25））或（应用程序=pop3和“服务器端口”！=110）或（应用程序=imap和“服务器端口”！=143）和（应用程序=imap或“服务器端口”！=143）；
var result=str.split（/\s*（和|或）\s*（？！[^（]*\）/）；
console.log（结果）；

---

.as console wrapper{max height:100%！important；top:0；}

如果存在多个嵌套层，则会导致额外的括号和混乱的拆分：

（“服务器端口”==1和（应用程序=smtp和（“服务器端口”！=25和“服务器端口”！=22）））

@Gerrit0，正确。我为这种嵌套的情况添加了一个替代方案，它不能在一个正则表达式中处理（至少不能在JS中处理）。不要使用正则表达式来解析上下文无关的语言！