Javascript jquery angularjs如何知道鼠标按下事件是否由浏览器的滚动条触发

我有一个小面板，如果按下鼠标下键，我就会关闭这个面板，基本上它会清除要显示的数据，只要在angularjs ng show的帮助下，如果没有数据，我就会隐藏它……应用程序在angularjs和jquery中

请在下面查找代码

 var closeSearchResultsIfClickedOutside = function (e) {

    if ($(e.target).parents('.searchResults').length === 0) {
        var scope = angular.element($("#searchContainer")).scope();
        scope.$apply(function () {

            /*Cancels any existing search*/
            if ($scope.defer != undefined) {
                $scope.defer.resolve();
            }

            $scope.showSearchResults = false;
            reinitialize();                
        });

        $("html").off("mousedown", closeSearchResultsIfClickedOutside);

        reinitializePanelsWidth();
    }      
};

---

但是，如果鼠标落在浏览器窗口的滚动条或任何滚动条上，我不想关闭此面板。请告诉我如何操作来解决上述问题。我没有捕获两个事件，请鼠标落下并单击，如果两个事件上的目标元素都匹配，那么我只关闭面板

 /*
  If mouse down and click on the same control, then only close the panel,
  Click event closing is added to avoid closing panel on scrollbar click.  
*/
var closeSearchResultsIfClickedOutside = function (e) {

    if (e.type === 'mousedown') { /* only if mouse down is outside of search panel then only close the panel. */
        if($(e.target).parents('.searchResults').length === 0)
        {
            isMouseDownOnSearchPanel = true;
        }
    else {
            isMouseDownOnSearchPanel = false;
        }
    }
    else if (e.type === 'click' && isMouseDownOnSearchPanel) {  /*click event is implemented to avoid closing when mouse down is on scrollbar. you dont get click get event for scrollbar*/
        var scope = angular.element($("#searchContainer")).scope();

        $("html").off("mousedown", closeSearchResultsIfClickedOutside);
        $("html").off("click", closeSearchResultsIfClickedOutside);
        isMouseDownOnSearchPanel = false;

        reinitializePanelsWidth();
    }       
};