如何检查javascript中是否存在object.subobject.SubSubSubObject？

层次结构可能很深，因此如何检查根对象中是否存在a属性？如果没有，那么创建它

我有下面的html

<div id="container">
   <div id="level-1">
       <input id="value-1" group="a.b" name="c" value="some-value-1">
   </div>
</div>

我的努力：

function traverse(id, obj) {
    var methodName = "traverse";
    var elementToTraverse = document.getElementById(id);
    var currentElementLength = elementToTraverse.childNodes.length;

    if (currentElementLength > 0) {

        var children = getChildNodes(elementToTraverse);
        for (var ch in children) {
            var currentChild = children[ch];
            //ignore the text nodes
            if (currentChild.nodeType == 3) {
                continue;
            }

            if (currentChild.nodeType == 1 && currentChild.childNodes.length > 0 && currentChild.id != "") {
                //call without the object argument as it has already been constructed.
                traverse(currentChild.id, obj);
            }
            else if (currentChild.nodeType == 1 && currentChild.id != "" && currentChild.getAttribute('name') != null) {
                if (DEBUG) {
                    logOnConsole(methodName, currentChild.getAttribute('name') + "--" + currentChild.id, logLevel.INFO);
                }
                var group = currentChild.getAttribute('group') || null;
                var name = currentChild.getAttribute('name');
                var value = getValue(currentChild);

                if (value == "" || value == undefined) {
                    if(group){
                        if(isNull(obj[group])){
                            obj[group] = new Object();
                        }
                        obj[group][name] = "";
                    }
                    else{
                        obj[name] = "";
                    }
                }
                else if(group){
                    if(isNull(obj[group])){
                        obj[group] = new Object();
                    }
                    obj[group][name] = value;
                }
                else {
                    obj[name] = value;
                }

            }
            else {

                if (DEBUG) {
                    logOnConsole(methodName, "Element not useful. \n" + currentChild.nodeName, logLevel.INFO);
                }
            }
        }
    }
    return obj;
}

我通过遍历（'container-id'，new Object（））调用它，但这将适用于组中的单个值，而不是嵌套结构。

试试这个

函数isExist（对象，路径）{
patharray=path.split（“.”）；
对于（变量i=0；idocument.body.innerHTML=isExist（{subobject:{subsubsubobject:{test:34}}}，'subobject.subsubsubobject'）添加一个例子和你的努力。我做了，它是否仍然被否决？它不会告诉哪个子对象不存在。那么我就不知道该创建哪一个了。所以要完成这个任务，我应该从根目录中逐个检查完整的层次结构吗？怎么说？@cafebabe1991不返回false，您可以返回patharray[i]，它是子对象不存在的，但您必须递归调用此函数来创建每个尚未构造的对象。（并且你没有在你的答案中创建对象）@cafebabe1991，而是返回任何东西，只是初始化缺少的对象，例如obj=obj[patharray[i]]={}；
function traverse(id, obj) {
    var methodName = "traverse";
    var elementToTraverse = document.getElementById(id);
    var currentElementLength = elementToTraverse.childNodes.length;

    if (currentElementLength > 0) {

        var children = getChildNodes(elementToTraverse);
        for (var ch in children) {
            var currentChild = children[ch];
            //ignore the text nodes
            if (currentChild.nodeType == 3) {
                continue;
            }

            if (currentChild.nodeType == 1 && currentChild.childNodes.length > 0 && currentChild.id != "") {
                //call without the object argument as it has already been constructed.
                traverse(currentChild.id, obj);
            }
            else if (currentChild.nodeType == 1 && currentChild.id != "" && currentChild.getAttribute('name') != null) {
                if (DEBUG) {
                    logOnConsole(methodName, currentChild.getAttribute('name') + "--" + currentChild.id, logLevel.INFO);
                }
                var group = currentChild.getAttribute('group') || null;
                var name = currentChild.getAttribute('name');
                var value = getValue(currentChild);

                if (value == "" || value == undefined) {
                    if(group){
                        if(isNull(obj[group])){
                            obj[group] = new Object();
                        }
                        obj[group][name] = "";
                    }
                    else{
                        obj[name] = "";
                    }
                }
                else if(group){
                    if(isNull(obj[group])){
                        obj[group] = new Object();
                    }
                    obj[group][name] = value;
                }
                else {
                    obj[name] = value;
                }

            }
            else {

                if (DEBUG) {
                    logOnConsole(methodName, "Element not useful. \n" + currentChild.nodeName, logLevel.INFO);
                }
            }
        }
    }
    return obj;
}