Javascript 正则表达式，提取键之间的文本

给定：

This is some text which could have 
line breaks and tabs before and after {code}
and I want them {code} to be replaced {code}in pairs{code} without any issues.

This is some text which could have 
line breaks and tabs before and after <code>
and I want them </code> to be replaced <code>in pairs</code> without any issues.

var sample1 = 'test test test {code}foo bar{code} {code}good to know{code}';
var regEx1 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r1 = sample1.replace(regEx1, '<code>$2</code>');

var sample2 = 'test test test {code}\tfoo bar{code} {code}\r\ngood to know{code}';
var regEx2 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r2 = sample2.replace(regEx2, '<code>$2</code>');

test test test {code}   foo bar{code} {code}
good to know{code}

我想要：

This is some text which could have 
line breaks and tabs before and after {code}
and I want them {code} to be replaced {code}in pairs{code} without any issues.

This is some text which could have 
line breaks and tabs before and after <code>
and I want them </code> to be replaced <code>in pairs</code> without any issues.

var sample1 = 'test test test {code}foo bar{code} {code}good to know{code}';
var regEx1 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r1 = sample1.replace(regEx1, '<code>$2</code>');

var sample2 = 'test test test {code}\tfoo bar{code} {code}\r\ngood to know{code}';
var regEx2 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r2 = sample2.replace(regEx2, '<code>$2</code>');

test test test {code}   foo bar{code} {code}
good to know{code}

JsFiddle：

简单工作文本示例：

This is some text which could have 
line breaks and tabs before and after {code}
and I want them {code} to be replaced {code}in pairs{code} without any issues.

This is some text which could have 
line breaks and tabs before and after <code>
and I want them </code> to be replaced <code>in pairs</code> without any issues.

var sample1 = 'test test test {code}foo bar{code} {code}good to know{code}';
var regEx1 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r1 = sample1.replace(regEx1, '<code>$2</code>');

var sample2 = 'test test test {code}\tfoo bar{code} {code}\r\ngood to know{code}';
var regEx2 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r2 = sample2.replace(regEx2, '<code>$2</code>');

test test test {code}   foo bar{code} {code}
good to know{code}

给出：

test test test <code>foo bar</code> <code>good to know</code>

非工作样本：

This is some text which could have 
line breaks and tabs before and after {code}
and I want them {code} to be replaced {code}in pairs{code} without any issues.

This is some text which could have 
line breaks and tabs before and after <code>
and I want them </code> to be replaced <code>in pairs</code> without any issues.

var sample1 = 'test test test {code}foo bar{code} {code}good to know{code}';
var regEx1 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r1 = sample1.replace(regEx1, '<code>$2</code>');

var sample2 = 'test test test {code}\tfoo bar{code} {code}\r\ngood to know{code}';
var regEx2 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r2 = sample2.replace(regEx2, '<code>$2</code>');

test test test {code}   foo bar{code} {code}
good to know{code}

给出：

This is some text which could have 
line breaks and tabs before and after {code}
and I want them {code} to be replaced {code}in pairs{code} without any issues.

This is some text which could have 
line breaks and tabs before and after <code>
and I want them </code> to be replaced <code>in pairs</code> without any issues.

var sample1 = 'test test test {code}foo bar{code} {code}good to know{code}';
var regEx1 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r1 = sample1.replace(regEx1, '<code>$2</code>');

var sample2 = 'test test test {code}\tfoo bar{code} {code}\r\ngood to know{code}';
var regEx2 = new RegExp('(\{code\})(.*?)(\{code\})', 'gi');
var r2 = sample2.replace(regEx2, '<code>$2</code>');

test test test {code}   foo bar{code} {code}
good to know{code}

---

看起来您只需要正确地转义第一个

{

，并使用正则表达式文本来修复在字符串中重复转义反斜杠的需要：

/(\{code\})([\s\S]*?)(\{code\})/gi

请注意，您甚至不需要在

{code}

s周围使用捕获括号：

/\{code\}([\s\S]*?)\{code\}/gi

---

@yckart，OP中没有任何东西表明它需要。是的，你完全正确！这只是一个旁注；）这是我的修正：

/\{\s*code\s*}（[\s\s]*？）\{\s*code\s*}/gi