Javascript ajax调用,但屏幕仍然向上
我有这个:Javascript ajax调用,但屏幕仍然向上,javascript,c#,asp.net-mvc-4,asp.net-ajax,Javascript,C#,Asp.net Mvc 4,Asp.net Ajax,我有这个: <div class="pull-left"> <div class="col-md-offset-0"> <input type="button" value="Save" class="btn btn-default pull-left" /> </div> </div> </div> <div
<div class="pull-left">
<div class="col-md-offset-0">
<input type="button" value="Save" class="btn btn-default pull-left" />
</div>
</div>
</div>
<div id="tabs-2">
@using (Ajax.BeginForm("EditPhotos", "Account",
new AjaxOptions()
{
InsertionMode = InsertionMode.Replace,
HttpMethod = "Post",
},
new { enctype = "multipart/form-data"}
))
//new { enctype = "multipart/form-data" }))
{
@Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>Photos</h4>
<hr />
视图:
OK,我可以保存照片,当我保存照片时,当前选项卡将保留选定选项卡。但保存后,屏幕会上升。因此,这似乎是一个完整的职位回来,而不是一个部分职位回来。因为在保存之前,我看到了三个选项卡。但在我保存后,标签会弹出。但是我做了一个ajax调用。那怎么可能呢
多谢各位
好吧,我现在有了这样的:
@section Scripts
{
<link href="@Url.Content("~/Content/themes/base/jquery-ui.css")" rel="stylesheet" type="text/css" />
<link href="@Url.Content("~/Content/Site.css")" rel="stylesheet" type="text/css" />
<script src="@Url.Content("~/Scripts/jquery-1.11.0.min.js")" type="text/javascript"></script>
<script src="@Url.Content("~/Scripts/jquery-ui-1.10.4.min.js")" type="text/javascript"></script>
<script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>
<script>
$(document).ready(function () {
$("#tabs").tabs();
$(document).on("click", ".btn", function () {
$("#tabs").tabs("select", window.location.hash);
//var param = $(document).getUrlParam('selectedTab');
//$('#tabs').tabs('select', param);
});
});
</script>
}
$(document).on("click", ".btn", function () {
$("#tabs").tabs();
$("#tabs").tabs("select", window.location.hash);
//var param = $(document).getUrlParam('selectedTab');
//$('#tabs').tabs('select', param);
});
$(document).ready(function () {
$.ajax({
url: resolveUrl("/Account/EditPhotos/"),
type: "POST",
processData: false,
contentType: false,
data: data,
success: function (response) {
//code after success
},
error: function (er) {
alert(er);
}
});
});
我再也看不到标签了
我有这个:
<div class="pull-left">
<div class="col-md-offset-0">
<input type="button" value="Save" class="btn btn-default pull-left" />
</div>
</div>
</div>
<div id="tabs-2">
@using (Ajax.BeginForm("EditPhotos", "Account",
new AjaxOptions()
{
InsertionMode = InsertionMode.Replace,
HttpMethod = "Post",
},
new { enctype = "multipart/form-data"}
))
//new { enctype = "multipart/form-data" }))
{
@Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>Photos</h4>
<hr />
但这一页仍在上升
如果我这样做:
$(document).on("click", ".btn", function(){
$("#ajaxUploadForm").ajaxForm({
iframe: true,
type: 'POST',
dataType: "json",
cache: false,
timeout: 1200000,
async: false,
beforeSubmit: function () {
//Do something here if needed like show in progress message
},
//success: function (result) {
// alert("sucess"
// },
error: function (xhr, textStatus, errorThrown) {
alert("Error uploading file");
}
});
});
与:
然后什么也没发生,我没有看到您的ajax代码发布,但是您的按钮是一个提交按钮,而不仅仅是一个按钮。你需要把它改成
<input type="button" value="Save" class="btn btn-default pull-left" />
您是如何通过表单执行ajax调用的,表单需要回发,因此页面会向上移动。要在不回发的情况下执行ajax调用,请参见这里,您的document.ready中有ajax调用。您需要将ajax调用放入一个click事件中,如下面我的回答中所示,该事件将触发按钮单击。
<div class="pull-left">
<div class="col-md-offset-0">
<input type="button" value="Save" class="btn btn-default pull-left" />
</div>
</div>
<input type="button" value="Save" class="btn btn-default pull-left" />
$(document).on("click", ".btn", function(){
...