Javascript 多重同时替换
在JS中,一次替换字符串中的多个内容(不受干扰)的最简单方法是什么?像 …所以它生产的是“国会大厦”,而不是“卡豪索尔大厦”?这个怎么样-Javascript 多重同时替换,javascript,string,replace,Javascript,String,Replace,在JS中,一次替换字符串中的多个内容(不受干扰)的最简单方法是什么?像 …所以它生产的是“国会大厦”,而不是“卡豪索尔大厦”?这个怎么样- function replaceArray(text, toBeReplacedArray, replacementArray) { for (var i = 0; i < toBeReplacedArray.length; i++) { var re = new RegExp(toBeReplacedArray[i], 'g'
function replaceArray(text, toBeReplacedArray, replacementArray) {
for (var i = 0; i < toBeReplacedArray.length; i++) {
var re = new RegExp(toBeReplacedArray[i], 'g');
text = text.replace(re, '__' + i + '__');
}
for (var i = 0; i < replacementArray.length; i++) {
var re = new RegExp('__' + i + '__', 'g');
text = text.replace(re, replacementArray[i]);
}
return text;
}
replaceArray("tar pit", ['tar', 'pit'], ['capitol', 'house']);
函数replaceArray(文本、toberReplaceArray、replacementArray){
对于(变量i=0;i
最简单的答案:regex+1比我的代码好得多,看不到我的代码胜过你:)。谢谢,太完美了:)
var replaceArray = function(str, from, to) {
var obj = {}, regex;
from.forEach(function(item, idx){obj[item] = to[idx];});
regex = new RegExp('(' + from.join('|') + ')', 'g');
return str.replace(regex, function(match){return obj[match]});
}
replaceArray("tar pit", ["tar", "pit"], ["capitol", "house"]);
function replaceArray(text, toBeReplacedArray, replacementArray) {
for (var i = 0; i < toBeReplacedArray.length; i++) {
var re = new RegExp(toBeReplacedArray[i], 'g');
text = text.replace(re, '__' + i + '__');
}
for (var i = 0; i < replacementArray.length; i++) {
var re = new RegExp('__' + i + '__', 'g');
text = text.replace(re, replacementArray[i]);
}
return text;
}
replaceArray("tar pit", ['tar', 'pit'], ['capitol', 'house']);