Javascript Immutablejs-更新嵌套映射和列表中的值
我有这个immutableJs映射:Javascript Immutablejs-更新嵌套映射和列表中的值,javascript,immutable.js,Javascript,Immutable.js,我有这个immutableJs映射: event: { days: [ { date: 1, sessions: [ { id: 1, name: 2, startTime: 1, endTime: 1,
event: {
days: [
{
date: 1,
sessions: [
{
id: 1,
name: 2,
startTime: 1,
endTime: 1,
description: 1,
detailsLink: 1,
details: {visible: true}
},
{
id: 2,
name: 2,
startTime: 2,
endTime: 2,
description: 2,
detailsLink: 2,
details: {visible: false}
},
{
id: 3,
name: 3,
startTime: 3,
endTime: 3,
description: 3,
detailsLink: 3,
details: {visible: true}
}
]
},
{
date: 2,
sessions: [
{
id: 1,
name: 2,
startTime: 1,
endTime: 1,
description: 1,
detailsLink: 1,
details: {visible: false}
},
{
id: 2,
name: 2,
startTime: 2,
endTime: 2,
description: 2,
detailsLink: 2,
details: {visible: false}
},
{
id: 3,
name: 3,
startTime: 3,
endTime: 3,
description: 3,
detailsLink: 3,
details: {visible: true}
}
]
}
]
}
我想更新那些可见的:真到可见:假。我尝试了很多不同的过滤方法,seq等等,但是没有成功
关于如何使用immutableJs实现这一点,您有什么想法吗?在ES6中,它可能很容易翻译成immutableJs
const notVisibleEvents={
…事件,
天:events.days.map(d=>{
返回{
D
sessions:d.sessions.map(s=>{
返回{
s
详情:{
…详细信息,
可见:假
}
};
})
};
})
};
派对迟到者,但这如何(假设您的数据位于名为data
的变量中):
data.setIn(["event", "days"],
data.getIn(["event", "days"]).map(day =>
day.set("sessions", day.get("sessions").map(session =>
session.setIn(['details', 'visible'], false)))
)
)