Javascript expressjs-无法处理请求

我正在学习nodejs/expressjs，并将其嵌入到springmvc模式中，因为我认为我可以保持文件的内聚性。但这并不像我想象的那样有效

server.js

const express = require('express');
const bodyParser= require('body-parser');
const MongoClient = require('mongodb').MongoClient;
const app = express();

var PeopleController = require('./controller/PeopleController.js')
var db;

app.all('/*', function(req, res, next) {
  var path = req.url;
  var controller;

  switch (true) {
    case /\/people.*/g.test(path):
      controller = new PeopleController();
      console.log("people");
      controller.process(req, res, next);
      break;
    case /\/foo.*/g.test(path):
      console.log("foo");
      break
    default:
      console.log("nada");
      break;
  }
});

const app = express();
...
controller = new PeopleController(app);

...
const PeopleController = require('./controller/PeopleController.js');

// apply PeopleController to '/people' route
app.use('/people', PeopleController);

PeopleController.js

const express = require('express');
const bodyParser= require('body-parser');
const MongoClient = require('mongodb').MongoClient;
const app = express();

var PeopleController = function PeopleController() {}

PeopleController.prototype.process = function (req, res, next) {
  var baseURL = '/people';

  console.log('path is ' + req.path);

  app.use(bodyParser.urlencoded({extended: true}));
  app.set('view engine', 'ejs');

  app.get(baseURL, (req, res) => {
    console.log('people get');
  });

  app.post(baseURL, (req, res) => {
    console.log('people post');
  });
};

module.exports = PeopleController;

const express = require('express'); // delete this
const app = express(); // delete this

//add this:
var PeopleController = function PeopleController(appInstance) {
  this.app = appInstance;
}

PeopleController.prototype.process = function (req, res, next) {
  var baseURL = '/people';
  var app = this.app;

  console.log('path is ' + req.path);

  app.use(bodyParser.urlencoded({extended: true}));
  app.set('view engine', 'ejs');

  app.get(baseURL, (req, res) => {
    console.log('people get');
  });

  app.post(baseURL, (req, res) => {
    console.log('people post');
  });
};

然后，当我做一个GET-on/people/I时，我会拿出下面的控制台

people
path is /people/

我希望app.get运行并获得以下输出：

people
path is /people/
people get

---

发生这种情况是因为在端口上只有一个Express侦听实例

在server.js中：

const express = require('express');
const bodyParser= require('body-parser');
const MongoClient = require('mongodb').MongoClient;
const app = express(); // we create an instance of Express
...
app.listen(process.ENV.PORT); //this specific instance listening on port

创建PeopleController的新实例时，必须通过server.js中的

应用程序

const app = express();
...
controller = new PeopleController(app);

...
const PeopleController = require('./controller/PeopleController.js');

// apply PeopleController to '/people' route
app.use('/people', PeopleController);

并在PeopleController.js中导入

const express = require('express');
const bodyParser= require('body-parser');
const MongoClient = require('mongodb').MongoClient;
const app = express();

var PeopleController = function PeopleController() {}

PeopleController.prototype.process = function (req, res, next) {
  var baseURL = '/people';

  console.log('path is ' + req.path);

  app.use(bodyParser.urlencoded({extended: true}));
  app.set('view engine', 'ejs');

  app.get(baseURL, (req, res) => {
    console.log('people get');
  });

  app.post(baseURL, (req, res) => {
    console.log('people post');
  });
};

module.exports = PeopleController;

const express = require('express'); // delete this
const app = express(); // delete this

//add this:
var PeopleController = function PeopleController(appInstance) {
  this.app = appInstance;
}

PeopleController.prototype.process = function (req, res, next) {
  var baseURL = '/people';
  var app = this.app;

  console.log('path is ' + req.path);

  app.use(bodyParser.urlencoded({extended: true}));
  app.set('view engine', 'ejs');

  app.get(baseURL, (req, res) => {
    console.log('people get');
  });

  app.post(baseURL, (req, res) => {
    console.log('people post');
  });
};

潜伏我强烈建议使用
express.router
如下：

PeopleController.js

const express = require('express');
const router = express.Router();

// then apply middleware
router.use(...);

// then define your endpoints
router.get('/', (req, res) => {
  console.log('get PeopleController.js root');
}

module.exports = router;

在server.js中

const app = express();
...
controller = new PeopleController(app);

...
const PeopleController = require('./controller/PeopleController.js');

// apply PeopleController to '/people' route
app.use('/people', PeopleController);

因此，现在当您请求GET/people时，您应该在节点上看到console.log。这种方法的最大好处是它保持了代码的整洁（没有基于路由的切换，您可以让express处理restful操作）
从我看到的情况来看，您创建了一个
app
的新实例，但它不监听任何端口
app.get
将请求与它正在侦听的端口相匹配。我想我更喜欢这种方法。您能否将此路由器/控制器概念应用于
app.method
，而不仅仅应用于中间件？嗨，char，我不确定我是否理解您的问题。这里的模式是对端点进行分组，例如，假设PeopleController有GET/sayHello和POST/reproduction，AnimalController有GET/makeNoise和POST/founders端点。您可以使用app.use（'/people'，PeopleController）和app.use（'/AnimalController'，AnimalController）来“附加”它们。最后将其与POST/动物/后代一起食用。如果您询问按方法对端点进行分组（例如，在一个文件中所有GET调用），那么这是一种我不熟悉的不同模式。这是一个干净的解决方案。谢谢，干得好。实际上，我最初是以与您类似的方式构建api的，直到github上的一个好家伙告诉我更好！