PHP在JavaScript集成代码中的应用
我尝试了几种选择,但都不起作用。。。。 我有密码PHP在JavaScript集成代码中的应用,javascript,php,mysql,phpmyadmin,timeline,Javascript,Php,Mysql,Phpmyadmin,Timeline,我尝试了几种选择,但都不起作用。。。。 我有密码 <script type="text/javascript"> $(document).ready(function() { <?php $sql = mysql_query("SELECT * FROM `info` WHERE `active` = '1' ORDER BY `id` DESC"); $id = 'id'; $title = 'title';
<script type="text/javascript">
$(document).ready(function() {
<?php
$sql = mysql_query("SELECT * FROM `info` WHERE `active` = '1' ORDER BY `id` DESC");
$id = 'id';
$title = 'title';
$content = 'content';
while ($rows = mysql_fetch_assoc($sql)){
?>
var timeline_data =
[
{
title: '<?php echo $rows[$title]; ?>',
content: '<?php echo $rows[$content]; ?>'
}
];
<?php
}
?>
var timeline = new Timeline($('#timeline'), timeline_data);
timeline.setOptions({
animation: true,
lightbox: true,
first_separator: true,
max: 2,
loadmore: 5,
separator: 'year',
columnMode: 'dual',
order: 'desc'
});
timeline.display();
});
</script>
$(文档).ready(函数(){
$(文档).ready(函数(){
$(文档).ready(函数(){
看起来你一直在用一个新的在这个物体上写字…看起来你一直在用一个新的在这个物体上写字。。。。
<script type="text/javascript">
$(document).ready(function() {
<?php
$sql = mysql_query("SELECT * FROM `info` WHERE `active` = '1' ORDER BY `id` DESC");
$id = 'id';
$title = 'title';
$content = 'content';
?>
var timeline_data =[];
<?php while ($rows = mysql_fetch_assoc($sql)){
?>
timeline_data[] =
{
title: '<?php echo $rows[$title]; ?>',
content: '<?php echo $rows[$content]; ?>'
}
;
<?php
}
?>
var timeline = new Timeline($('#timeline'), timeline_data);
timeline.setOptions({
animation: true,
lightbox: true,
first_separator: true,
max: 2,
loadmore: 5,
separator: 'year',
columnMode: 'dual',
order: 'desc'
});
timeline.display();
});
</script>