Javascript 使用PHP中的JQuery.grep从Json Txt文件筛选结果

Javascript 使用PHP中的JQuery.grep从Json Txt文件筛选结果,javascript,php,jquery,json,grep,Javascript,Php,Jquery,Json,Grep,我能够毫无问题地将JSON结果拉入表中,但是当涉及到基于PHP$\u GET变量过滤结果时,我似乎无法返回结果集 我的桌子很简单: <table id="displaythatdata"> <thead> <tr> <th>Meter</th> <th>Address</th> <th>City</th> <th>Da

我能够毫无问题地将JSON结果拉入表中,但是当涉及到基于PHP
$\u GET
变量过滤结果时,我似乎无法返回结果集

我的桌子很简单:

<table id="displaythatdata">
  <thead>
    <tr>
      <th>Meter</th>
      <th>Address</th>
      <th>City</th>
      <th>Date</th>
      <th>Status</th>
      <th>Location</th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td>that</td>
      <td>that2</td>
      <td>that3</td>
      <td>that4</td>
      <td>that5</td>
      <td>that6</td>
    </tr>
  </tbody>
</table>
我的PHP是标准的:

$getthedivision = $_GET['getregion'];
$gettheplat = $_GET['getplat'];
我的JSON看起来像:

[{"ID":1,"UUID":"5D2F830-8757-F80FA715A78E","SPID":86810,"METER":"900A","LOCADDRESS":"123 MEADOW RD","CITY":"SANTA ANA","DIVISION":"SAN DIEGO","PLAT":"1145-C08","ADDRESS_NUM":123,"ADDRESS_EVODD":1,"ADDRESS_STREET":"MEADOW RD","GRD_BELOW_SU":null,"GRD_ABOVE_SU":null,"MANIFOLD_METER":null"},

关于为什么我可以基于PHP
$\u GET
变量返回结果集,有什么想法吗?我可以把它们打印出来,这样我就知道它们正在被设置。我看到
.grep()
是使用jQuery JSON进行过滤的方法。对象也是这样吗?

是否要查看JSON对象的每一部分,并获得区域和平台特定的部分?我的目标是使用我的$\u get变量进行过滤。。。我需要返回所有字段,但根据$\u GET vars的设置进行排序。它应该在该数组中对其进行排序。
[{"ID":1,"UUID":"5D2F830-8757-F80FA715A78E","SPID":86810,"METER":"900A","LOCADDRESS":"123 MEADOW RD","CITY":"SANTA ANA","DIVISION":"SAN DIEGO","PLAT":"1145-C08","ADDRESS_NUM":123,"ADDRESS_EVODD":1,"ADDRESS_STREET":"MEADOW RD","GRD_BELOW_SU":null,"GRD_ABOVE_SU":null,"MANIFOLD_METER":null"},