Javascript 这可以用正则表达式完成吗？在字符串中找到我的密钥

我有regex

/[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}/gm

来匹配这样的键模式

aaaaaaaaaaaaaaaaaaaaaaa

现在我想修改这个正则表达式以匹配这些示例中的键模式：

"AAAAA-AAAAA-AAAAA",
"dasd:AAAAA-AAAAA-AAAAA.ds",
"AAAAA-AAAAA-AAAAA:dsad",
"das.AAAAA-AAAAA-AAAAA",
"df:AAAAA-AAAAA-AAAAA:das",
"AAAAA-AAAAA-AAAAA asdas",
"dsad adf AAAAA-AAAAA-AAAAA",
"AAAAA-AAAAA-AAAAA adasd asd"

"AAAAA-AAAAA-AAAAA-aaaaaaa",
"sadasAAAAA-AAAAA-AAAAA",
"AAAAA-AAAAA-AAAAAdasd",
"dsa-AAAAA-AAAAA-AAAAA-das",
"adsAAAAA-AAAAA-AAAAAasd"

但不要在这些例子中找到匹配项：

"AAAAA-AAAAA-AAAAA",
"dasd:AAAAA-AAAAA-AAAAA.ds",
"AAAAA-AAAAA-AAAAA:dsad",
"das.AAAAA-AAAAA-AAAAA",
"df:AAAAA-AAAAA-AAAAA:das",
"AAAAA-AAAAA-AAAAA asdas",
"dsad adf AAAAA-AAAAA-AAAAA",
"AAAAA-AAAAA-AAAAA adasd asd"

"AAAAA-AAAAA-AAAAA-aaaaaaa",
"sadasAAAAA-AAAAA-AAAAA",
"AAAAA-AAAAA-AAAAAdasd",
"dsa-AAAAA-AAAAA-AAAAA-das",
"adsAAAAA-AAAAA-AAAAAasd"

因此，描述是：如果

[a-zA-Z0-9]

或

-

在键模式之前或之后，我不想匹配它

我试过类似的方法（^[a-zA-Z0-9]）？[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}（^[a-zA-Z0-9]）？，但这不起作用

---

这可以只使用正则表达式来完成，还是需要额外的代码来完成？

您可以在左右两侧使用单词边界

\b

来防止部分匹配，并且在模式的末尾使用负向前看

（？！-）

来不直接在当前位置的左侧声明连字符

\b[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}\b(?!-)

const regex=/\b[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}\b（？）/；
[
“AAAAA-AAAAA-AAAAA”，
“dasd:AAAAA-AAAAA-AAAAA.ds”，
“AAAAA-AAAAA-AAAAA:dsad”，
“das.AAAAA-AAAAA-AAAAA”，
“df:AAAAA-AAAAA-AAAAA:das”，
“AAAAA-AAAAA-AAAAA asdas”，
“dsad adf AAAAA-AAAAA-AAAAA”，
“AAAAA-AAAAA-AAAAA adasd”，
“AAAAA-AAAAA-AAAAA-AAAAAAAA”，
“sadasAAAAA-aaaaaa-aaaaaa”，
“AAAAA-AAAAA-AAAAA DASD”，
“dsa-AAAAA-AAAAA-AAAAA-das”，
“adsAAAAA-AAAAA-AAAAA ASD”
].forEach（s=>{
常量匹配=s.match（正则表达式）；
log（匹配？${s}-->${match[0]}`:`${s}-->不匹配`）；
})

像这样吗<代码>\b[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}\b（？），或者使用一个捕获组

^-\n]*\b（[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-zA-Z0-9]{5}-[a-Z0-9]-[a-Z0-9]{5}-[a-zA-Z0-9]}-$$$$

，我不知道为什么这样做。谢谢：）@GuerricP我的意思是，每个字符串都是一个新字符串，用于尝试匹配。不是全部