Javascript 处理导航以提醒未保存的更改

Javascript 处理导航以提醒未保存的更改,javascript,react-native,react-navigation,expo,react-navigation-stack,Javascript,React Native,React Navigation,Expo,React Navigation Stack,我正在使用react navigation中的defaultGetStateForAction截取我的导航,这样我就可以提醒我的用户有未保存的数据,并给他继续导航和删除未保存数据或先保存数据的选项。该数据存储在更高的组件状态中,可通过screenProps提供的功能访问该状态 所以。。。这是我的密码: const CreateAnimalStack = createStackNavigator({ CreateAnimal: { screen: createAnimalScreen },

我正在使用react navigation中的defaultGetStateForAction截取我的导航,这样我就可以提醒我的用户有未保存的数据,并给他继续导航和删除未保存数据或先保存数据的选项。该数据存储在更高的组件状态中,可通过screenProps提供的功能访问该状态

所以。。。这是我的密码:

const CreateAnimalStack = createStackNavigator({
    CreateAnimal: { screen: createAnimalScreen },
    ListAnimals: { screen: listAnimalsScreen },
    DetailAnimal: { screen: detailAnimalScreen },
    ReviewAnimal: { screen: reviewAnimalScreen },
    ListMarks: { screen: listMarksScreen },
    CreateMark: { screen: createMarkScreen },
}, {
        initialRouteName: 'CreateAnimal',
    });

const defaultGetStateForAction = CreateAnimalStack.router.getStateForAction;

CreateAnimalStack.router.getStateForAction = (action, state) => {
    if (
        state &&
        action.type === NavigationActions.BACK &&
        state.routeName === 'CreateAnimal' &&
        state.routes[state.index].routeName === 'ReviewAnimal' &&
        state.index === 1
    ) {
        Alert.alert(
            'Alert Title',
            'My Alert Msg',
            [
                { text: 'Ask me later', onPress: () => console.log('Ask me later pressed') },
                {
                    text: 'Cancel',
                    onPress: () => {
                        return null;
                    },
                    style: 'cancel',
                },
                {
                    text: 'OK', onPress: () => {
                        const routes = [
                            { routeName: 'CreateAnimal' },
                        ];
                        return {
                            ...state,
                            routes,
                            index: 0,
                        };
                    }
                },
            ],
            { cancelable: false },
        );
        return state;

    } 
    return defaultGetStateForAction(action, state);
};

export default CreateAnimalStack;

我认为这里的主要问题是,
警报
没有阻塞,因此导航仍会发生在警报后面

也就是说,从中,您应该在
if
语句中返回
null
:它将取消导航

if (...) {
  Alert.alert(
      'Alert Title',
      'My Alert Msg',
      // ...
  );

  return null;
}
import { HeaderBackButton } from 'react-navigation';

class YourScreen extends Component {
  static navigationOptions = ({ navigation }) => {
    const onBack = {
      Alert.alert(
        'Alert Title',
        'My Alert Msg',
        [
            { text: 'Ask me later', onPress: () => console.log('Ask me later pressed') },
            {
                text: 'Cancel',
                style: 'cancel',
            },
            {
                text: 'OK', onPress: () => {
                    navigation.goBack();
                }
            },
        ],
        { cancelable: false }
      );
    }

    return {
      headerLeft: <HeaderBackButton  onPress={() => onBack()} />
    }
}
然后在Alert OK按钮解析中,您必须重新调度导航操作(而不是返回状态),但问题是您没有可用的
dispatch
<代码>分派来自
AppContainer
。一种方法是创建一个存储导航器的
NavigationService
,如,然后从
dispatch
导出它

// ...
{
    text: 'OK', onPress: () => {
        const action = NavigationActions.navigate({ routeName: 'CreateAnimal', params: {}});

        // here you have to call dispatch from the AppContainer navigator (NavigationService ?)
        NavigationService.dispatch(action);
    }
},
在我看来,所有这些代码都很脆弱,非常丑陋

我建议您首先探索一种完全不同的方法,例如,使用自定义onPress回调将默认的
headerLeft
组件替换为screen
navigationOptions
,而不是监听状态更改

下面是一个简单的未经测试的示例,它从react navigation导入默认的左按钮

if (...) {
  Alert.alert(
      'Alert Title',
      'My Alert Msg',
      // ...
  );

  return null;
}
import { HeaderBackButton } from 'react-navigation';

class YourScreen extends Component {
  static navigationOptions = ({ navigation }) => {
    const onBack = {
      Alert.alert(
        'Alert Title',
        'My Alert Msg',
        [
            { text: 'Ask me later', onPress: () => console.log('Ask me later pressed') },
            {
                text: 'Cancel',
                style: 'cancel',
            },
            {
                text: 'OK', onPress: () => {
                    navigation.goBack();
                }
            },
        ],
        { cancelable: false }
      );
    }

    return {
      headerLeft: <HeaderBackButton  onPress={() => onBack()} />
    }
}
从“反应导航”导入{HeaderBackButton};
类YourScreen扩展组件{
静态导航选项=({navigation})=>{
const onBack={
警惕,警惕(
“警报标题”,
“我的提醒信息”,
[
{text:'Ask me later',onPress:()=>console.log('Ask me later pressed')},
{
文本:“取消”,
样式:“取消”,
},
{
文本:“确定”,按:()=>{
navigation.goBack();
}
},
],
{可取消:false}
);
}
返回{
headerLeft:onBack()}/>
}
}

我认为这里的主要问题是
警报
没有阻塞,因此导航仍会在警报后进行

也就是说,从中,您应该在
if
语句中返回
null
:它将取消导航

if (...) {
  Alert.alert(
      'Alert Title',
      'My Alert Msg',
      // ...
  );

  return null;
}
import { HeaderBackButton } from 'react-navigation';

class YourScreen extends Component {
  static navigationOptions = ({ navigation }) => {
    const onBack = {
      Alert.alert(
        'Alert Title',
        'My Alert Msg',
        [
            { text: 'Ask me later', onPress: () => console.log('Ask me later pressed') },
            {
                text: 'Cancel',
                style: 'cancel',
            },
            {
                text: 'OK', onPress: () => {
                    navigation.goBack();
                }
            },
        ],
        { cancelable: false }
      );
    }

    return {
      headerLeft: <HeaderBackButton  onPress={() => onBack()} />
    }
}
然后在Alert OK按钮解析中,您必须重新调度导航操作(而不是返回状态),但问题是您没有可用的
dispatch
<代码>分派来自
AppContainer
。一种方法是创建一个存储导航器的
NavigationService
,如,然后从
dispatch
导出它

// ...
{
    text: 'OK', onPress: () => {
        const action = NavigationActions.navigate({ routeName: 'CreateAnimal', params: {}});

        // here you have to call dispatch from the AppContainer navigator (NavigationService ?)
        NavigationService.dispatch(action);
    }
},
在我看来,所有这些代码都很脆弱,非常丑陋

我建议您首先探索一种完全不同的方法,例如,使用自定义onPress回调将默认的
headerLeft
组件替换为screen
navigationOptions
,而不是监听状态更改

下面是一个简单的未经测试的示例,它从react navigation导入默认的左按钮

if (...) {
  Alert.alert(
      'Alert Title',
      'My Alert Msg',
      // ...
  );

  return null;
}
import { HeaderBackButton } from 'react-navigation';

class YourScreen extends Component {
  static navigationOptions = ({ navigation }) => {
    const onBack = {
      Alert.alert(
        'Alert Title',
        'My Alert Msg',
        [
            { text: 'Ask me later', onPress: () => console.log('Ask me later pressed') },
            {
                text: 'Cancel',
                style: 'cancel',
            },
            {
                text: 'OK', onPress: () => {
                    navigation.goBack();
                }
            },
        ],
        { cancelable: false }
      );
    }

    return {
      headerLeft: <HeaderBackButton  onPress={() => onBack()} />
    }
}
从“反应导航”导入{HeaderBackButton};
类YourScreen扩展组件{
静态导航选项=({navigation})=>{
const onBack={
警惕,警惕(
“警报标题”,
“我的提醒信息”,
[
{text:'Ask me later',onPress:()=>console.log('Ask me later pressed')},
{
文本:“取消”,
样式:“取消”,
},
{
文本:“确定”,按:()=>{
navigation.goBack();
}
},
],
{可取消:false}
);
}
返回{
headerLeft:onBack()}/>
}
}