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Javascript PHP SQL数据库的下拉列表_Javascript_Php_Jquery_Sql_Database - Fatal编程技术网

Javascript PHP SQL数据库的下拉列表

Javascript PHP SQL数据库的下拉列表,javascript,php,jquery,sql,database,Javascript,Php,Jquery,Sql,Database,如何将TXTRACKID获取到数据库中,它只能从下拉列表中获取一个 <label><b>Track/Section</b></label></br> <select id="soflow" name="track_type" onChange="add1()"> <option value="">Select Tracks</option> <option value="ABM">

如何将TXTRACKID获取到数据库中,它只能从下拉列表中获取一个

<label><b>Track/Section</b></label></br>
<select id="soflow" name="track_type" onChange="add1()">

  <option value="">Select Tracks</option>
  <option value="ABM">ABM</option>
  <option value="STEM">STEM</option>
  <option va;lue="ICT">ICT</option>
  <option value="HAS">HAS</option>
  <option value="BM">BM</option>
  <option value="HUMMS">HUMMS</option>
</select>

<input id="txttrackid" class="txttrackid" name="txttrackid" type="text"> </br>
下面是Javascript代码

   <script>
      function add1() { 
      var ddlvalue = document.getElementById("soflow").value;
      var up1 = document.getElementById("txttrackid");
      //console.log(ddlvalue);
      if (ddlvalue == 'ABM')
        up1.value = '1';
      else if (ddlvalue == 'STEM')
        up1.value = '2';
      else if (ddlvalue == 'ICT')
        up1.value = '3';
      else if (ddlvalue == 'HAS')
        up1.value = '4';
      else if (ddlvalue == 'BM')
        up1.value = '5';
      else if (ddlvalue == 'HUMMS')
        up1.value = '6';

    }

    </script>

当我在数据库中输入时,只有下拉列表中的一个会显示出来。我重写了代码,它更容易获得设置值,选择值,然后在需要时使用

函数add1{ var selval=$soflow.val;//获取选择时选择框的值 如果值不是空的,则ifselval!={// $TXTRACKID.valseval;//在TXTRACKID中设置值 } } 轨道/区段 选择曲目 反弹道导弹 茎 信息通信技术 有 BM 哼