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Javascript 使用AngularJS访问嵌套JSON

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Javascript 使用AngularJS访问嵌套JSON,javascript,json,angularjs,mobile,cordova,Javascript,Json,Angularjs,Mobile,Cordova,我正在尝试使用angular.js、hammer.js和topcoat制作和移动webapp 我在显示Json文件中的数据时遇到了一些问题，例如： { "version": "1", "artists": { "artist1": { "name": "artist1name", "jpeg": "../img/artist/artist1.jpg", "albums": { "album1": {

我正在尝试使用angular.js、hammer.js和topcoat制作和移动webapp

我在显示Json文件中的数据时遇到了一些问题，例如：

{
"version": "1",
"artists": {
    "artist1": {
        "name": "artist1name",
        "jpeg": "../img/artist/artist1.jpg",
        "albums": {
            "album1": {
                "type": "cd",
                "title": "titlealbum1",
                "subtitle": "subtitlealbum1",
                "jpeg": "../img/album1.jpg",
                "price": "12.00",
                "anystring1": "anystring1album1",
                "anystring2": "anystring2album1"
            },
            "album2": [{
                "type": "cd",
                "title": "titlealbum2",
                "subtitle": "subtitlealbum2",
                "jpeg": "../img/album2.jpg",
                "price": "12.00",
                "anystring1": "anystring1album2",
                "anystring2": "anystring2album2"
            }],
            "album3": [{
                "type": "cd",
                "title": "titlealbum3",
                "subtitle": "subtitlealbum3",
                "jpeg": "../img/album3.jpg",
                "price": "13.00",
                "anystring1": "anystring1album3",
                "anystring2": "anystring2album3"
            }]
        }
    },
    "artist2": {
        "name": "artist2name",
        "jpeg": "../img/artist/artist2.jpg",


{
  "version": "1",
  "artists": [
    {
      "name": "artist1name",
      "jpeg": "../img/artist/artist1.jpg",
      "albums": [
        {
          "type": "cd",
          "title": "titlealbum1",
          "subtitle": "subtitlealbum1",
          "jpeg": "../img/album1.jpg",
          "price": "12.00",
          "anystring1": "anystring1album1",
          "anystring2": "anystring2album1"
        },
        {
          "type": "cd",
          "title": "titlealbum2",
          "subtitle": "subtitlealbum2",
          "jpeg": "../img/album2.jpg",
          "price": "12.00",
          "anystring1": "anystring1album2",
          "anystring2": "anystring2album2"
        },
        {
          "type": "cd",
          "title": "titlealbum3",
          "subtitle": "subtitlealbum3",
          "jpeg": "../img/album3.jpg",
          "price": "13.00",
          "anystring1": "anystring1album3",
          "anystring2": "anystring2album3"
        }
      ]
    },
    {
      "name": "artist2name",
      "jpeg": "../img/artist/artist2.jpg",
      "albums": []
    }
  ]
}
我的js文件如下所示：

angular.module('list', [])
function ListCtrl ($scope, $http) {
$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data)
{
$scope.artists = data.artists; // response data 
$scope.albums = data.artists.albums; /this is where im getting trouble
});        
};

<body ng-app="list">

<h3>Titulos</h3>

<div ng-controller="ListCtrl">
<ul ng-repeat="artist in artists">
        <li >{{artist.name}}</li>

    </ul>
</div>

<div ng-controller="ListCtrl">
<ul ng-repeat="album in albums">
        <li >{{album.title}}</li>  //not working here. 

    </ul>
</div>

$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data) {
    $scope.artists = [];
    angular.forEach(data.artists, function(value, key) {
        $scope.artists.push(value);
    });
    $scope.isVisible = function(name){
        return true;// return false to hide this artist's albums
    };
});
我的HTML文件如下所示：

angular.module('list', [])
function ListCtrl ($scope, $http) {
$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data)
{
$scope.artists = data.artists; // response data 
$scope.albums = data.artists.albums; /this is where im getting trouble
});        
};

<body ng-app="list">

<h3>Titulos</h3>

<div ng-controller="ListCtrl">
<ul ng-repeat="artist in artists">
        <li >{{artist.name}}</li>

    </ul>
</div>

<div ng-controller="ListCtrl">
<ul ng-repeat="album in albums">
        <li >{{album.title}}</li>  //not working here. 

    </ul>
</div>

$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data) {
    $scope.artists = [];
    angular.forEach(data.artists, function(value, key) {
        $scope.artists.push(value);
    });
    $scope.isVisible = function(name){
        return true;// return false to hide this artist's albums
    };
});


提托洛斯

    

  • {{artist.name}
    • 



    

  • {{album.title}
    • //不在这里工作。

我想显示所有相册，如果我的用户选择了特定的艺术家，我想过滤这些相册。 这里的问题是我将如何选择这个嵌套的json。顺便说一句，artist.name显示正确。

第二个问题是，我将如何使用文本字段过滤这些艺术家

我建议这样做：

angular.module('list', [])
function ListCtrl ($scope, $http) {
$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data)
{
$scope.artists = data.artists; // response data 
$scope.albums = data.artists.albums; /this is where im getting trouble
});        
};

<body ng-app="list">

<h3>Titulos</h3>

<div ng-controller="ListCtrl">
<ul ng-repeat="artist in artists">
        <li >{{artist.name}}</li>

    </ul>
</div>

<div ng-controller="ListCtrl">
<ul ng-repeat="album in albums">
        <li >{{album.title}}</li>  //not working here. 

    </ul>
</div>

$http({method: 'GET', url: 'json/json_price_1.json'}).success(function(data) {
    $scope.artists = [];
    angular.forEach(data.artists, function(value, key) {
        $scope.artists.push(value);
    });
    $scope.isVisible = function(name){
        return true;// return false to hide this artist's albums
    };
});
然后：

<div ng-controller="ListCtrl">
    <ul>
        <li ng-repeat="artist in artists">{{artist.name}}</li>
    </ul>
    <ul ng-repeat="artist in artists" ng-show="isVisible(artist.name)">
        <li ng-repeat="album in artist.albums">{{album.title}}</li>
    </ul>
</div>



    

  • {{artist.name}
    • 



    

  • {{album.title}
    •
检查

回答您的问题“我将如何选择此嵌套json？”

回答您的问题“如何使用文本字段过滤这些艺术家？”



    

  • {{album.title}
    •
所有问题都是从JSON开始的。我建议您简化JSON，并将每个
Artist
和
Album
作为对象，将
Artists
和
Albums
作为对象数组

试试这个：

{
"version": "1",
"artists": {
    "artist1": {
        "name": "artist1name",
        "jpeg": "../img/artist/artist1.jpg",
        "albums": {
            "album1": {
                "type": "cd",
                "title": "titlealbum1",
                "subtitle": "subtitlealbum1",
                "jpeg": "../img/album1.jpg",
                "price": "12.00",
                "anystring1": "anystring1album1",
                "anystring2": "anystring2album1"
            },
            "album2": [{
                "type": "cd",
                "title": "titlealbum2",
                "subtitle": "subtitlealbum2",
                "jpeg": "../img/album2.jpg",
                "price": "12.00",
                "anystring1": "anystring1album2",
                "anystring2": "anystring2album2"
            }],
            "album3": [{
                "type": "cd",
                "title": "titlealbum3",
                "subtitle": "subtitlealbum3",
                "jpeg": "../img/album3.jpg",
                "price": "13.00",
                "anystring1": "anystring1album3",
                "anystring2": "anystring2album3"
            }]
        }
    },
    "artist2": {
        "name": "artist2name",
        "jpeg": "../img/artist/artist2.jpg",


{
  "version": "1",
  "artists": [
    {
      "name": "artist1name",
      "jpeg": "../img/artist/artist1.jpg",
      "albums": [
        {
          "type": "cd",
          "title": "titlealbum1",
          "subtitle": "subtitlealbum1",
          "jpeg": "../img/album1.jpg",
          "price": "12.00",
          "anystring1": "anystring1album1",
          "anystring2": "anystring2album1"
        },
        {
          "type": "cd",
          "title": "titlealbum2",
          "subtitle": "subtitlealbum2",
          "jpeg": "../img/album2.jpg",
          "price": "12.00",
          "anystring1": "anystring1album2",
          "anystring2": "anystring2album2"
        },
        {
          "type": "cd",
          "title": "titlealbum3",
          "subtitle": "subtitlealbum3",
          "jpeg": "../img/album3.jpg",
          "price": "13.00",
          "anystring1": "anystring1album3",
          "anystring2": "anystring2album3"
        }
      ]
    },
    {
      "name": "artist2name",
      "jpeg": "../img/artist/artist2.jpg",
      "albums": []
    }
  ]
}
在我的示例中，数组可以是空的（artist2没有分配唱片集）

您的
列表Ctrl
中也有错误的提示，在您知道正确的
艺术家之前，您无法分配和显示相册。如果你想展示所有艺术家的所有专辑，你需要遍历所有艺术家

控制器示例：



angular.module('list', []);

function ListCtrl($scope, $http) {
  $http({
    method: 'GET',
    url: 'json_price_1.json'
  }).success(function(data) {
    $scope.artists = data.artists; // response data
    $scope.albums = [];
    angular.forEach(data.artists, function(artist, index) {
      angular.forEach(artist.albums, function(album, index){
        $scope.albums.push(album);
      });
    });
  });
}

下面是基于jessie示例修改的Plunkr:
    

  • 
{{artist.name}}
    

      

    • {{key}}-{{val}
      • 

    

    • 



在哪里生成json？相册中的模式不一致。第一张相册中没有数组，其他两张相册中有数组。在将数据传递到我生成的文件之前，必须重新映射数据。但是php脚本将在以后生成它。每次我使用JsonLint来验证我的Json，所以请忽略这个错误。谢谢json的结构远远不够理想。这不是关于是否有效…而是应该使用对象数组…这将使设置Angular变得更容易。非常感谢！你的例子很有启发性。我在这方面很新手，你的回答太棒了！