Javascript 如何使用正则表达式匹配没有顶级域的链接？

我使用next regex（linkify regex的更新版本）来匹配链接和不匹配电子邮件

(\s*|[^a-zA-Z0-9.\+_\/"\>\-]|^)(?:([a-zA-Z0-9\+_\-]+(?:\.[a-zA-Z0-9\+_\-]+)*@)?(http:\/\/|https:\/\/|ftp:\/\/|scp:\/\/){1}?((?:(?:[a-zA-Z0-9][a-zA-Z0-9_%\-_+]*\.)+))(?:[a-zA-Z]{2,})((?::\d{1,5}))?((?:[\/|\?](?:[\-a-zA-Z0-9_%#*&+=~!?,;:.\/]*)*)[\-\/a-zA-Z0-9_%#*&+=~]|\/?)?)([^a-zA-Z0-9\+_\/"\<\-]|$)

（2）以下几种：：（（a-zA-zA-zA-Z0-9-9-9-9-9-9-10-10-10-10-9-9-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-10-5-10）以下以下以下几种：：：（以下以下）以下以下几种：：：（，（，（以下以下：：：：：：（以下以下以下以下以下：：：（（：（：（：（：（：（：（：（：（：（：（：（a）以下：：：：（：（：（：（：（：（：（：（：（：（：（：（：（：（：（：（：（：（a）（a-a-a-a-a-a-a-a-a-a-a-a-zA-a-zA-zA-zA-a-zA-zA-zA-a-zA-zA-zA-zA-zA-zA-zA-Z0-Z0（（？：[\/\\？]）（？：[\-a-zA-Z0-9%.+=！，；：.\/]*）*）[\-\/a-zA-Z0-9%.&+=[\%.+=]这应该是“修改最少的”用于匹配没有顶级的域的表达式版本：

(\s*|[^a-zA-Z0-9.\+_\/"\>\-]|^)(?:([a-zA-Z0-9\+_\-]+(?:\.[a-zA-Z0-9\+_\-]+)*@)?(http:\/\/|https:\/\/|ftp:\/\/|scp:\/\/){1}?((?:[a-zA-Z0-9][a-zA-Z0-9_%\-_+.]*)(?:\.[a-zA-Z]{2,})?)((?::\d{1,5}))?((?:[\/|\?](?:[\-a-zA-Z0-9_%#*&+=~!?,;:.\/]*)*)[\-\/a-zA-Z0-9_%#*&+=~]|\/?)?)([^a-zA-Z0-9\+_\/"\<\-]|$)

为此：

(
 (?:
  [a-zA-Z0-9]
  [a-zA-Z0-9_%\-_+.]* (?# the . is in the character class here for subdomains)
 )
 (?:
  \.
  [a-zA-Z]{2,}
 )?                   (?# this TLD is optional)
)

---

您期望的输出是什么？我希望正则表达式与我在帖子中添加的URL匹配。非常感谢您的解释和演示！这很有帮助！

(
 (?:
  [a-zA-Z0-9]
  [a-zA-Z0-9_%\-_+.]* (?# the . is in the character class here for subdomains)
 )
 (?:
  \.
  [a-zA-Z]{2,}
 )?                   (?# this TLD is optional)
)