Javascript 表排序器，子组排序

我尝试制作一个小部件，它可以在一个表中对一组行分别进行排序，同时使行组与分组行保持一致。我不知道如何解决这个问题

编辑：我想对非colspan列进行排序。每个组都应该作为一个子表

在JSFIDLE中的基本设置，有人能把我推向正确的方向吗

编辑：新的JSFIDLE

这里有一个不使用tablesorter的

关键是使用tbody元素对行进行分组。然后对每个tbody中除最后一行以外的所有行进行排序

该表可能如下所示：

  <table class="sortable">
    <thead>
        <tr> <th></th> <th>A-head</th> <th>B-head</th> <th>C-head</th> </tr>
    </thead>
    <tfoot>
        <tr> <td></td> <td>A-foot</td> <td>B-foot</td> <td>C-foot</td></tr>
    </tfoot>

    <tbody class='sortable'>
        <tr> <td>DDD</td><td> r1c1</td> <td>r1c2</td> <td>r1c3</td> </tr>
        <tr> <td>AAA</td><td> r2c1</td> <td>r2c2</td> <td>r2c3</td> </tr>
        <tr> <td>CCC</td><td> r3c1</td> <td>r3c2</td> <td>r3c3</td> </tr>
        <tr> <td>BBB</td><td> r4c1</td> <td>r4c2</td> <td>r4c3</td> </tr>
        <tr> <td colspan="4">summary info for the first group of rows</td> </tr>
    </tbody>

    <tbody class='sortable'>
        <tr> <td>Zorro</td><td> r5c1</td> <td>r5c2</td> <td>r5c3</td> </tr>
        <tr> <td>Caleb</td><td> r6c1</td> <td>r6c2</td> <td>r6c3</td> </tr>
        <tr> <td>Momo</td><td> r7c1</td> <td>r7c2</td> <td>r7c3</td> </tr>
        <tr> <td>Wolfie</td><td> r8c1</td> <td>r8c2</td> <td>r8c3</td> </tr>
        <tr> <td colspan="4">summary info for rowgroup #2</td> </tr>
    </tbody>
     ...

  function SortIt() {
      jQuery('table.sortable > tbody.sortable').each(function(index,tbody) {
        var $rowGroup = jQuery(tbody);

        // select all but the last row in the tbody
        var rows = $rowGroup.find('tr:not(last-child)').get();

        var sortDirection = $rowGroup.is('.sorted-asc') ? -1 : 1;

        // Set a custom property on each row - 'sortKey', the key to sort.
        // This example uses the text in the first column. It could use
        // any column, or any content in the row.
        jQuery.each(rows, function(index, row) {
            row.sortKey = jQuery(row).children('td').first().text();
        });

        // actually sort the rows
        rows.sort(function(a, b) {
            if (a.sortKey < b.sortKey) return -sortDirection;
            if (a.sortKey > b.sortKey) return sortDirection;
            return 0;
        });

        // retain the summary row - the last one
        var summaryRow = $rowGroup.find("tr:last-child");

        // remove all the rows from the tbody
        $rowGroup.find("tr").remove();

        // append the rows in sorted order
        jQuery.each(rows, function(index, row) {
            $rowGroup.append(row);
            row.sortKey = null;
        });

        // append the final row
        $rowGroup.append(summaryRow);

        if (sortDirection == 1) { $rowGroup.addClass('sorted-asc'); }
        else {$rowGroup.removeClass('sorted-asc'); }

      });
  }

它的排序fn可能如下所示：

  <table class="sortable">
    <thead>
        <tr> <th></th> <th>A-head</th> <th>B-head</th> <th>C-head</th> </tr>
    </thead>
    <tfoot>
        <tr> <td></td> <td>A-foot</td> <td>B-foot</td> <td>C-foot</td></tr>
    </tfoot>

    <tbody class='sortable'>
        <tr> <td>DDD</td><td> r1c1</td> <td>r1c2</td> <td>r1c3</td> </tr>
        <tr> <td>AAA</td><td> r2c1</td> <td>r2c2</td> <td>r2c3</td> </tr>
        <tr> <td>CCC</td><td> r3c1</td> <td>r3c2</td> <td>r3c3</td> </tr>
        <tr> <td>BBB</td><td> r4c1</td> <td>r4c2</td> <td>r4c3</td> </tr>
        <tr> <td colspan="4">summary info for the first group of rows</td> </tr>
    </tbody>

    <tbody class='sortable'>
        <tr> <td>Zorro</td><td> r5c1</td> <td>r5c2</td> <td>r5c3</td> </tr>
        <tr> <td>Caleb</td><td> r6c1</td> <td>r6c2</td> <td>r6c3</td> </tr>
        <tr> <td>Momo</td><td> r7c1</td> <td>r7c2</td> <td>r7c3</td> </tr>
        <tr> <td>Wolfie</td><td> r8c1</td> <td>r8c2</td> <td>r8c3</td> </tr>
        <tr> <td colspan="4">summary info for rowgroup #2</td> </tr>
    </tbody>
     ...

  function SortIt() {
      jQuery('table.sortable > tbody.sortable').each(function(index,tbody) {
        var $rowGroup = jQuery(tbody);

        // select all but the last row in the tbody
        var rows = $rowGroup.find('tr:not(last-child)').get();

        var sortDirection = $rowGroup.is('.sorted-asc') ? -1 : 1;

        // Set a custom property on each row - 'sortKey', the key to sort.
        // This example uses the text in the first column. It could use
        // any column, or any content in the row.
        jQuery.each(rows, function(index, row) {
            row.sortKey = jQuery(row).children('td').first().text();
        });

        // actually sort the rows
        rows.sort(function(a, b) {
            if (a.sortKey < b.sortKey) return -sortDirection;
            if (a.sortKey > b.sortKey) return sortDirection;
            return 0;
        });

        // retain the summary row - the last one
        var summaryRow = $rowGroup.find("tr:last-child");

        // remove all the rows from the tbody
        $rowGroup.find("tr").remove();

        // append the rows in sorted order
        jQuery.each(rows, function(index, row) {
            $rowGroup.append(row);
            row.sortKey = null;
        });

        // append the final row
        $rowGroup.append(summaryRow);

        if (sortDirection == 1) { $rowGroup.addClass('sorted-asc'); }
        else {$rowGroup.removeClass('sorted-asc'); }

      });
  }

---

您想如何进行排序？您希望它按宽行排序，然后按拆分行排序，就像Finder/Explorer按字母顺序在文件夹上排序，然后在子文件夹上排序一样吗？很抱歉，不清楚，我想按非colspan列排序。每个组都应该作为一个子表。宽colspan行是否附加到它们下面的单行？或者它们是否固定在适当的位置，例如，无论其他行如何排序，它们都显示为第三行和第六行？colspan行附加到它上面的行，并且不会每x索引重复一次。更新的JSFIDLE示例只是为了让您知道，我已经更新了我的fork of tablesorter，现在可以对包含多个tbodies的表进行排序。退房