Javascript 遍历数组并删除包含特定单词的所有值

我有这个阵列：

suggestions = [ "the dog", 
                "the cat", 
                "the boat",
                "boat engine",
                "boat motor",
                "motor oil"
              ];

如何遍历数组并删除包含特定单词的所有条目

例如，删除包含单词“the”的所有实体，使数组变为：

[ "boat engine",
  "boat motor",
  "motor oil"
];

---

创建新阵列可能更容易：

var correct = [],
    len = suggestions.length,
    i = 0,
    val;

for (; i < len; ++i) {
    val = suggestions[i];
    if (val.indexOf('the') === -1) {
        correct.push(val);
    }
}

var correct=[]，
len=建议长度，
i=0，
瓦尔；
对于（；i

使用ECMAScript 5的强大功能：

suggestions.reduce (
  function (r, s) {!(/\bthe\b/.test (s)) && r.push (s); return r; }, []);

尝试使用正则表达式

var suggestions = [ "the dog", 
                "the cat", 
                "the boat",
                "boat engine",
                "boat motor",
                "motor oil"
              ];
var filtered = [],
    len = suggestions.length,
    val,
    checkCondition = /\bthe\b/;

for (var i =0; i < len; ++i) {
    val = suggestions[i];
    if (!checkCondition.test(val)) {
        filtered.push(val);
    }
}

var建议=[“狗”，
“猫”，
“船”，
“船用发动机”，
“船用马达”，
“机油”
];
筛选的var=[]，
len=建议长度，
瓦尔，
checkCondition=/\b\b/；
对于（变量i=0；i

---

我将使用以下设置：

var suggestions = [
    "the dog",
    "the cat",
    "he went then",
    "boat engine",
    "another either thing",
    "some string the whatever"
];

function filterWord(arr, filter) {
    var i = arr.length, cur,
        re = new RegExp("\\b" + filter + "\\b");
    while (i--) {
        cur = arr[i];
        if (re.test(cur)) {
            arr.splice(i, 1);
        }
    }
}

filterWord(suggestions, "the");
console.log(suggestions);

演示：

它向后循环，正确地检查要查找的单词（使用

\b

标识符作为单词边界），并删除任何匹配项

如果要生成包含匹配项的新数组，请正常循环，并将所有不匹配项推送到新数组。你可以用这个：

var suggestions = [
    "the dog",
    "the cat",
    "he went then",
    "boat engine",
    "another either thing",
    "some string the whatever"
];

function filterWord(arr, filter) {
    var i, j, cur, ret = [],
        re = new RegExp("\\b" + filter + "\\b");
    for (i = 0, j = arr.length; i < j; i++) {
        cur = arr[i];
        if (!re.test(cur)) {
            ret.push(cur);
        }
    }
    return ret;
}

var newSuggestions = filterWord(suggestions, "the");
console.log(newSuggestions);

var建议=[
“狗”，
“猫”，
“他当时去了”，
“船用发动机”，
“另一件事”，
“一些字符串什么的”
];
函数过滤器字（arr，过滤器）{
变量i，j，cur，ret=[]，
re=新的RegExp（“\\b”+过滤器+”\\b”）；
对于（i=0，j=arr.length；i

---

演示：

向后循环，并使用正则表达式查找单词，然后

拼接

匹配的项目