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Javascript 使用PHP上传视频_Javascript_Php_File_Upload_Video Streaming - Fatal编程技术网

Javascript 使用PHP上传视频

Javascript 使用PHP上传视频,javascript,php,file,upload,video-streaming,Javascript,Php,File,Upload,Video Streaming,我正在尝试使用此代码上载视频。 但是下面的代码对我不起作用,有人能帮忙吗? 如果需要,请更正代码。 我不太懂php <?php mysql_connect("localhost","root","123456789"); mysql_select_db("vid"); if(isset($_POST['submit'])) { $name = $_FILES['file']['name']; $name = $_FILES['file']['temp_na

我正在尝试使用此代码上载视频。

但是下面的代码对我不起作用,有人能帮忙吗?

如果需要,请更正代码。 我不太懂php

<?php
mysql_connect("localhost","root","123456789");
mysql_select_db("vid");

if(isset($_POST['submit']))
{
        $name = $_FILES['file']['name'];
        $name = $_FILES['file']['temp_name'];

        move_uploaded_file($temp,"uploaded/".$name);
        $url = "http://localhost/video/uploaded/$name";
        mysql_query("INSERT INTO `videos` VALUE ('','$name','$url') ");
}

?>





<body>
<a href="videos.php">Videos</a>
<form action="upload.php" method="POST" enctype="multipart/form-data">

<input type="file" name="file" />
<br><br>
<input type="submit" name="submit" value="Upload" />
</form>
<?php
if(isset($_POST['submit']))
{
        echo "<br/>".$name." has been Uploaded";
}

?>


</body>

$name=$\u文件['file']['temp\u name']可能应该是
$temp=$\u FILES['file']['temp\u name']你不这么认为吗?你好,阿卡什-请阅读,因为你的代码目前易受SQL注入攻击。