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Javascript 将公历日期转换为jalali_Javascript_Date_Jalali Calendar - Fatal编程技术网

Javascript 将公历日期转换为jalali

Javascript 将公历日期转换为jalali,javascript,date,jalali-calendar,Javascript,Date,Jalali Calendar,我有这样一个函数: var date = new Date(); var d = date.getDate(); var m = date.getMonth(); var y = date.getFullYear(); var hdr = {}; 还有一个函数可以转换它: function gregorian_to_jalali($g_y,$g_m,$g_d,$mod=''){ $g_y=tr_num($g_y); $g_m=tr_num($g_m); $g_d=tr_num($g_

我有这样一个函数:

var date = new Date();
var d = date.getDate();
var m = date.getMonth();
var y = date.getFullYear();

var hdr = {};
还有一个函数可以转换它:

function gregorian_to_jalali($g_y,$g_m,$g_d,$mod=''){
    $g_y=tr_num($g_y); $g_m=tr_num($g_m); $g_d=tr_num($g_d);
 $d_4=$g_y%4;
 $g_a=array(0,0,31,59,90,120,151,181,212,243,273,304,334);
 $doy_g=$g_a[(int)$g_m]+$g_d;
 if($d_4==0 and $g_m>2)$doy_g++;
 $d_33=(int)((($g_y-16)%132)*.0305);
 $a=($d_33==3 or $d_33<($d_4-1) or $d_4==0)?286:287;
 $b=(($d_33==1 or $d_33==2) and ($d_33==$d_4 or $d_4==1))?78:(($d_33==3 and $d_4==0)?80:79);
 if((int)(($g_y-10)/63)==30){$a--;$b++;}
 if($doy_g>$b){
  $jy=$g_y-621; $doy_j=$doy_g-$b;
 }else{
  $jy=$g_y-622; $doy_j=$doy_g+$a;
 }
 if($doy_j<187){
  $jm=(int)(($doy_j-1)/31); $jd=$doy_j-(31*$jm++);
 }else{
  $jm=(int)(($doy_j-187)/30); $jd=$doy_j-186-($jm*30); $jm+=7;
 }
 return($mod=='')?array($jy,$jm,$jd):$jy.$mod.$jm.$mod.$jd;
}
2此外,这: 我做错了什么

这行的作用是:var hdr={}

让我解释一下我的全部工作,我使用日历,我想将其更改为jalali日历,这是我的功能:

$('#calendar').fullCalendar({
            header: hdr,
            editable: true,
            droppable: true, // this allows things to be dropped onto the calendar !!!
            drop: function drop(date) {
                // this function is called when something is dropped

                // retrieve the dropped element's stored Event Object
                var originalEventObject = $(this).data('eventObject');

                // we need to copy it, so that multiple events don't have a reference to the same object
                var copiedEventObject = $.extend({}, originalEventObject);

                // assign it the date that was reported
                copiedEventObject.start = date;

                // render the event on the calendar
                // the last `true` argument determines if the event "sticks" (http://arshaw.com/fullcalendar/docs/event_rendering/renderEvent/)
                $('#calendar').fullCalendar('renderEvent', copiedEventObject, true);

                // is the "remove after drop" checkbox checked?
                if ($('#drop-remove').is(':checked')) {
                    // if so, remove the element from the "Draggable Events" list
                    $(this).remove();
                }
            },
            windowResize: function windowResize(event, ui) {
                $('#calendar').fullCalendar('render');
            }
        });

我过去常在日历中更改日历系统。

我过去常在日历中更改日历系统。

将公历日期转换为日历日期的简单方法

function gregorian_to_jalali(gy, gm, gd){
    g_d_m = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334];
    if (gy > 1600) {
            jy = 979;
            gy -= 1600;
    }
    else {
            jy = 0;
            gy -= 621;
    }
    gy2 = (gm > 2) ? (gy + 1) : gy;
    days = (365 * gy) + (parseInt((gy2 + 3) / 4)) - (parseInt((gy2 + 99) / 100)) + (parseInt((gy2 + 399) / 400)) - 80 + gd + g_d_m[gm - 1];
    jy += 33 * (parseInt(days / 12053));
    days %= 12053;
    jy += 4 * (parseInt(days / 1461));
    days %= 1461;
    if (days > 365) {
            jy += parseInt((days - 1) / 365);
            days = (days - 1) % 365;
    }
    jm = (days < 186) ? 1 + parseInt(days / 31) : 7 + parseInt((days - 186) / 30);
    jd = 1 + ((days < 186) ? (days % 31) : ((days - 186) % 30));

    var resultY = jy.toString();
    var resultM = jm < 10 ? "0" + jm.toString() : jm.toString();
    var resultD = jd < 10 ? "0" + jd.toString() : jd.toString();
    return [resultY, resultM, resultD];
}

将公历日期转换为Jalali日期的简单方法

function gregorian_to_jalali(gy, gm, gd){
    g_d_m = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334];
    if (gy > 1600) {
            jy = 979;
            gy -= 1600;
    }
    else {
            jy = 0;
            gy -= 621;
    }
    gy2 = (gm > 2) ? (gy + 1) : gy;
    days = (365 * gy) + (parseInt((gy2 + 3) / 4)) - (parseInt((gy2 + 99) / 100)) + (parseInt((gy2 + 399) / 400)) - 80 + gd + g_d_m[gm - 1];
    jy += 33 * (parseInt(days / 12053));
    days %= 12053;
    jy += 4 * (parseInt(days / 1461));
    days %= 1461;
    if (days > 365) {
            jy += parseInt((days - 1) / 365);
            days = (days - 1) % 365;
    }
    jm = (days < 186) ? 1 + parseInt(days / 31) : 7 + parseInt((days - 186) / 30);
    jd = 1 + ((days < 186) ? (days % 31) : ((days - 186) % 30));

    var resultY = jy.toString();
    var resultM = jm < 10 ? "0" + jm.toString() : jm.toString();
    var resultD = jd < 10 ? "0" + jd.toString() : jd.toString();
    return [resultY, resultM, resultD];
}

您提供的信息不完整。Try 2应该可以工作,并且转换结果存储在变量hdr中。建议:有一些免费代码可能会有所帮助。快速的谷歌搜索返回了这个站点。你知道这个{}在这里做什么吗:var hdr={}?它正在创建一个空对象,该对象将填充gregorian_to_jalaly,m,dy的返回值。您应该正确格式化代码,将所有or的实例替换为| |,将所有or的实例替换为&&,修复语法错误,如$g_a[int$g_m],并用var声明所有变量。最后,提供tr_num函数。在此之前,无法提供任何帮助。在您修复gregorian_to_jalali函数之前,其余的都是毫无意义的。您提供的信息是不完整的。Try 2应该可以工作,并且转换结果存储在变量hdr中。建议:有一些免费代码可能会有所帮助。快速的谷歌搜索返回了这个站点。你知道这个{}在这里做什么吗:var hdr={}?它正在创建一个空对象,该对象将填充gregorian_to_jalaly,m,dy的返回值。您应该正确格式化代码,将所有or的实例替换为| |,将所有or的实例替换为&&,修复语法错误,如$g_a[int$g_m],并用var声明所有变量。最后,提供tr_num函数。在此之前,无法提供任何帮助。在您修复gregorian_to_jalali函数之前,其余的都是毫无意义的。
function gregorian_to_jalali(gy, gm, gd){
    g_d_m = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334];
    if (gy > 1600) {
            jy = 979;
            gy -= 1600;
    }
    else {
            jy = 0;
            gy -= 621;
    }
    gy2 = (gm > 2) ? (gy + 1) : gy;
    days = (365 * gy) + (parseInt((gy2 + 3) / 4)) - (parseInt((gy2 + 99) / 100)) + (parseInt((gy2 + 399) / 400)) - 80 + gd + g_d_m[gm - 1];
    jy += 33 * (parseInt(days / 12053));
    days %= 12053;
    jy += 4 * (parseInt(days / 1461));
    days %= 1461;
    if (days > 365) {
            jy += parseInt((days - 1) / 365);
            days = (days - 1) % 365;
    }
    jm = (days < 186) ? 1 + parseInt(days / 31) : 7 + parseInt((days - 186) / 30);
    jd = 1 + ((days < 186) ? (days % 31) : ((days - 186) % 30));

    var resultY = jy.toString();
    var resultM = jm < 10 ? "0" + jm.toString() : jm.toString();
    var resultD = jd < 10 ? "0" + jd.toString() : jd.toString();
    return [resultY, resultM, resultD];
}