jquery表单成功显示从服务器生成的消息

我有

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在这里，您可以使用任何变量来存储AJAX响应，而不是使用函数（数据）

尝试使用以下代码，而不是您现有的代码

 $.ajax({
   type: "POST",
   url: "the/form",
   data: $(\'.target\').serialize(),
   success: function(data) { // data is a callback variable which stores info echoed in PHP file during transfer, so you have to $message there to get it here
    alert(data); // this will alert it
    }
  });

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您必须在ajax文件（the/form）中回显消息

不确定为什么，但当回显“data”不返回任何内容时，我仍然接受这个答案。

 $.ajax({
   type: "POST",
   url: "the/form",
   data: $(\'.target\').serialize(),
   success: function() {
    alert("done");
    // how to show the infoMessage ?
    }
  });

 $.ajax({
   type: "POST",
   url: "the/form",
   data: $(\'.target\').serialize(),
   success: function(data) { // data is a callback variable which stores info echoed in PHP file during transfer, so you have to $message there to get it here
    alert(data); // this will alert it
    }
  });

$.ajax({
   type: "POST",
   url: "the/form",
   data: $(\'.target\').serialize(),
   success: function(data) {
    alert(data); //data contains the ajax response
    $("#infoMessage").html(data); //you set here where to ajax response will be displayed
    }
  });

$.ajax({
   type: "POST",
   url: "the/form",
   data: $(\'.target\').serialize(),
   success: function(data) {
    //alert("done");
    $('#infoMessage').html(data);
    }
  });