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Jquery 将显示/隐藏与';幻灯片';效果,如何在偏移处开始/停止滑动?_Jquery_Jquery Ui - Fatal编程技术网

Jquery 将显示/隐藏与';幻灯片';效果,如何在偏移处开始/停止滑动?

Jquery 将显示/隐藏与';幻灯片';效果,如何在偏移处开始/停止滑动?,jquery,jquery-ui,Jquery,Jquery Ui,我有一个菜单,可以打开 $('.my_menu').show('slide', {direction:'up'}, 500, function() {}, function() {}); 接近 $('.my_menu').hide('slide', {direction:'up'}, 200, function() {}, function() {}); 现在,当它关闭时,我不希望菜单一直回到隐藏状态,我希望看到菜单的某些部分,以提供一个视觉提示,表明确实有东西在那里 显示/隐藏命令是否有偏

我有一个菜单,可以打开

$('.my_menu').show('slide', {direction:'up'}, 500, function() {}, function() {});
接近

$('.my_menu').hide('slide', {direction:'up'}, 200, function() {}, function() {});
现在,当它关闭时,我不希望菜单一直回到隐藏状态,我希望看到菜单的某些部分,以提供一个视觉提示,表明确实有东西在那里

显示/隐藏命令是否有偏移选项

/T

您是否尝试过:

var height = $('.my_menu').outerHeight() - 4; // show 4 pixels
$('.my_menu').hide('slide', {direction:'up', distance: height}, 200, function() {}, function() {});
(看一看)