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jquery自动完成抛出-->&引用;parsererror";,SyntaxError:无效的标签_Jquery_Json_Flask_Jquery Ui Autocomplete - Fatal编程技术网

jquery自动完成抛出-->&引用;parsererror";,SyntaxError:无效的标签

jquery自动完成抛出-->&引用;parsererror";,SyntaxError:无效的标签,jquery,json,flask,jquery-ui-autocomplete,Jquery,Json,Flask,Jquery Ui Autocomplete,在自动完成之后,我想到了这个 $("#search").autocomplete({ source: function (request, response) { $.ajax({ url: "/search", dataType: "jsonp", data: { feat

在自动完成之后,我想到了这个

$("#search").autocomplete({
            source: function (request, response) {
                $.ajax({
                    url: "/search",
                    dataType: "jsonp",
                    data: {
                        featureClass: "P",
                        style: "full",
                        maxRows: 12,
                        name_startsWith: request.term
                    },
                    success: function (data) {
                        response($.map(data.username, function (item) {
                            return {
                                label: item.name,
                                value: item.name
                            };
                        }));
                    },
                    error: function (data) {

                    }
                });
            },
            minLength: 2,
            select: function (event, ui) {

            },

        });
然而,我从来没有点击过
success:function(data){..}
,但总是点击
error:function(data){

Firebug显示错误:
“parsererror”,语法错误:无效标签

/search
url在服务器端生成以下内容:

def search():
    data = None
    if 'name_startsWith' in request.args:
        q = request.args['name_startsWith']
        data = User.query(ndb.AND(User.firstname >= q, User.firstname <= q + u'\ufffd')).fetch(12)
        js = []
        for user in data:
            js.append({'name' : user.fullname()})         
    return jsonify(username=js)
def search():
数据=无
如果request.args中的“name_startsWith”:
q=request.args['name\u startsWith']

data=User.query(ndb.AND(User.firstname>=q,User.firstname将数据类型更改为
json
,因为您的响应是一个json对象,请求被发送到同一个域,所以不需要jsonp

$("#search").autocomplete({
            source: function (request, response) {
                $.ajax({
                    url: "/search",
                    dataType: "json",
                    data: {
                        featureClass: "P",
                        style: "full",
                        maxRows: 12,
                        name_startsWith: request.term
                    },
                    success: function (data) {
                        response($.map(data.username, function (item) {
                            return {
                                label: item.name,
                                value: item.name
                            };
                        }));
                    },
                    error: function (data) {

                    }
                });
            },
            minLength: 2,
            select: function (event, ui) {

            },

        });
演示:
演示:

我怀疑用户名包含一些无效字符,如
”。您可以共享其中的字符集吗确保。
{“用户名”:[{“名称”:“Kave Kory”}]}
虽然您的数据类型是jsonp,但我看不到任何东西,但这是一个json响应,请将数据类型更改为“json”+1,非常感谢。它很有效。但在您的回答中,您再次看到了
jsdonp
;-)