右对齐时，基于jQuery的下拉菜单不起作用

我有以下脚本，几乎完美地工作：

HTML:

<div class="menu">
    <div class="navigation1">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 1</div>
        <div class="items">icon Reports 1</div>
        <div class="items">icon Other 1</div>
    </div>
    <div class="navigation2">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 2</div>
        <div class="items">icon Reports 2</div>
        <div class="items">icon Other 2</div>
    </div>
</div> 

.menu {
    position: relative;
    background-color:silver;
    font-family:Arial;
    font-size:12px;
    height:25px;
}

.navigation1 {
    float:left;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation2 {
    float:right;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation1::selection, .navigation2::selection { background:transparent; }
.navigation1::-moz-selection, .navigation2::-moz-selection { background:transparent; }

.navigation1:hover, .navigation2:hover {
    background-color:gray;
}

.navigation1.active, .navigation2.active {
    border:1px solid black;
    border-bottom-color:white;
    padding:4px 9px;
    background-color: white;
    position:relative;
    z-index:1;
}

.dropdown {
    display:none;
    border:1px solid black;
    border-bottom-width:2px;
    background-color:white;
    position:absolute;
    top:24px;
    padding:5px 10px;
    cursor:pointer;
}​

$(document).click(function(event) {
    $('.navigation1.active, .navigation2.active').click();
    $('.navigation1').removeClass("active");
});

$('.dropdown').each(function() {
    $(this).css('left', $(this).prev().position().left);
});

$('.navigation1, .navigation2').click(function(event) {
    $(this).siblings('.navigation1.active, .navigation2.active').click();
    $(this).toggleClass('active').next().toggle();
    event.stopPropagation();
});

$('.navigation1, .navigation2').disableSelection();​

jQuery:

<div class="menu">
    <div class="navigation1">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 1</div>
        <div class="items">icon Reports 1</div>
        <div class="items">icon Other 1</div>
    </div>
    <div class="navigation2">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 2</div>
        <div class="items">icon Reports 2</div>
        <div class="items">icon Other 2</div>
    </div>
</div> 

.menu {
    position: relative;
    background-color:silver;
    font-family:Arial;
    font-size:12px;
    height:25px;
}

.navigation1 {
    float:left;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation2 {
    float:right;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation1::selection, .navigation2::selection { background:transparent; }
.navigation1::-moz-selection, .navigation2::-moz-selection { background:transparent; }

.navigation1:hover, .navigation2:hover {
    background-color:gray;
}

.navigation1.active, .navigation2.active {
    border:1px solid black;
    border-bottom-color:white;
    padding:4px 9px;
    background-color: white;
    position:relative;
    z-index:1;
}

.dropdown {
    display:none;
    border:1px solid black;
    border-bottom-width:2px;
    background-color:white;
    position:absolute;
    top:24px;
    padding:5px 10px;
    cursor:pointer;
}​

$(document).click(function(event) {
    $('.navigation1.active, .navigation2.active').click();
    $('.navigation1').removeClass("active");
});

$('.dropdown').each(function() {
    $(this).css('left', $(this).prev().position().left);
});

$('.navigation1, .navigation2').click(function(event) {
    $(this).siblings('.navigation1.active, .navigation2.active').click();
    $(this).toggleClass('active').next().toggle();
    event.stopPropagation();
});

$('.navigation1, .navigation2').disableSelection();​

问题：

<div class="menu">
    <div class="navigation1">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 1</div>
        <div class="items">icon Reports 1</div>
        <div class="items">icon Other 1</div>
    </div>
    <div class="navigation2">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 2</div>
        <div class="items">icon Reports 2</div>
        <div class="items">icon Other 2</div>
    </div>
</div> 

.menu {
    position: relative;
    background-color:silver;
    font-family:Arial;
    font-size:12px;
    height:25px;
}

.navigation1 {
    float:left;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation2 {
    float:right;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation1::selection, .navigation2::selection { background:transparent; }
.navigation1::-moz-selection, .navigation2::-moz-selection { background:transparent; }

.navigation1:hover, .navigation2:hover {
    background-color:gray;
}

.navigation1.active, .navigation2.active {
    border:1px solid black;
    border-bottom-color:white;
    padding:4px 9px;
    background-color: white;
    position:relative;
    z-index:1;
}

.dropdown {
    display:none;
    border:1px solid black;
    border-bottom-width:2px;
    background-color:white;
    position:absolute;
    top:24px;
    padding:5px 10px;
    cursor:pointer;
}​

$(document).click(function(event) {
    $('.navigation1.active, .navigation2.active').click();
    $('.navigation1').removeClass("active");
});

$('.dropdown').each(function() {
    $(this).css('left', $(this).prev().position().left);
});

$('.navigation1, .navigation2').click(function(event) {
    $(this).siblings('.navigation1.active, .navigation2.active').click();
    $(this).toggleClass('active').next().toggle();
    event.stopPropagation();
});

$('.navigation1, .navigation2').disableSelection();​

唯一的问题是右边的菜单，当它的下拉菜单下拉时，文本最终会换行，因为下拉菜单不够宽。如何根据其中的文本将下拉列表设置为正确的宽度，但允许它在左侧突出

基本上，对于左侧菜单，下拉菜单从菜单的右侧突出

对于右菜单，下拉菜单应该从菜单的左侧突出

jsFiddle:

<div class="menu">
    <div class="navigation1">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 1</div>
        <div class="items">icon Reports 1</div>
        <div class="items">icon Other 1</div>
    </div>
    <div class="navigation2">icon Home</div>
    <div class="dropdown">
        <div class="items">icon Default 2</div>
        <div class="items">icon Reports 2</div>
        <div class="items">icon Other 2</div>
    </div>
</div> 

.menu {
    position: relative;
    background-color:silver;
    font-family:Arial;
    font-size:12px;
    height:25px;
}

.navigation1 {
    float:left;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation2 {
    float:right;
    padding:5px 10px 5px 10px;
    cursor:pointer;
}

.navigation1::selection, .navigation2::selection { background:transparent; }
.navigation1::-moz-selection, .navigation2::-moz-selection { background:transparent; }

.navigation1:hover, .navigation2:hover {
    background-color:gray;
}

.navigation1.active, .navigation2.active {
    border:1px solid black;
    border-bottom-color:white;
    padding:4px 9px;
    background-color: white;
    position:relative;
    z-index:1;
}

.dropdown {
    display:none;
    border:1px solid black;
    border-bottom-width:2px;
    background-color:white;
    position:absolute;
    top:24px;
    padding:5px 10px;
    cursor:pointer;
}​

$(document).click(function(event) {
    $('.navigation1.active, .navigation2.active').click();
    $('.navigation1').removeClass("active");
});

$('.dropdown').each(function() {
    $(this).css('left', $(this).prev().position().left);
});

$('.navigation1, .navigation2').click(function(event) {
    $(this).siblings('.navigation1.active, .navigation2.active').click();
    $(this).toggleClass('active').next().toggle();
    event.stopPropagation();
});

$('.navigation1, .navigation2').disableSelection();​

---

所以首先，请检查一下

---

如果您看到了预期的结果，那么实现它的方法是为第二个下拉列表

div

提供第二个类，例如

second

。然后创建一个css类

。第二个{left:auto！important；right:0}

。那你应该很好。

所以首先，请检查这个

---

如果您看到了预期的结果，那么实现它的方法是为第二个下拉列表

div

提供第二个类，例如

second

。然后创建一个css类

。第二个{left:auto！important；right:0}

。你应该很好。

你不能对每个下拉列表使用相同的下拉类，你应该使用单独的类或id@oshirowanen你解决了你的问题吗？是的，但是，我对同一个脚本有另一个问题：你不能对每个下拉列表使用相同的下拉类，您应该使用分离类或id@oshirowanen你解决了你的问题吗？是的，但是，我对同一个脚本还有另一个问题：