Jquery 选择选项中的csv json值

Jquery 选择选项中的csv json值,jquery,json,csv,Jquery,Json,Csv,我有这样的json值。 我需要获取批发商名称的值,并使用jquery将其放入select选项值中 [ { "outletid":6117, "wholesaleid":3, "outletuniid":"OLT1006117", "outletname":"new outlet", "outletaddressone":"address one", "outletaddresstwo":"address two

我有这样的json值。 我需要获取批发商名称的值,并使用jquery将其放入select选项值中

[  
   {  
      "outletid":6117,
      "wholesaleid":3,
      "outletuniid":"OLT1006117",
      "outletname":"new outlet",
      "outletaddressone":"address one",
      "outletaddresstwo":"address two",
      "outletlandmark":"Landmark new",
      "outletemail":null,
      "outletcontactperson":"Ajin",
      "outletcontact":"9787132227",
      "itcassert":"qwertyui",
      "status":0,
      "createdDate":"2016-02-01 17:34:24",
      "wholesalecode":"WSH1003",
      "wholesalename":"Whoshop new",
      "wholesaleemail":"who@gmail.com",
      "wholesalecontact":"8754181719",
      "wholesaletlname":"ajin1,ajin3,ajin2",
      "wholesaletlcontact":"1234567890,1234587452,8754181719",
      "wholesaleaddress":""
   }
]
ajin
阿金3
Ahin2
您已经使用了
split()

var json=[{
“outletid”:6117,
“批发商ID”:3,
“outletuniid”:“OLT1006117”,
“outletname”:“新门店”,
“outletaddressone”:“AddressOne”,
“outletaddresstwo”:“AddressTwo”,
“outletlandmark”:“Landmark new”,
“outletemail”:空,
“outletcontactperson”:“Ajin”,
“outletcontact”:“9787132227”,
“itcasert”:“qwertyui”,
“状态”:0,
“createdDate”:“2016-02-01 17:34:24”,
“批发商代码”:“WSH1003”,
“批发”:“Whoshop new”,
“批发商电子邮件”:who@gmail.com",
“批发商联系人”:“8754181719”,
“批发商名称”:“ajin1、ajin3、ajin2”,
“批发商联系人”:“1234567890012345874528754181719”,
“批发商地址”:”
}]
var arr=json[0]。批发商名称。拆分(',');
美元(arr)。每个(功能(i,项目){
$(“#ddl”).append(“+item+”);
})

欢迎来到StackOverflow!请看一看!我们希望您在提出请求之前,能够在项目中投入自己的努力。自己动手吧,如果你有代码库要处理,就回来吧。我们帮助解决问题,但没有代码交付服务!
<option>ajin1</option>
<option>ajin3</option>
<option>ajin2</option>