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Jquery SQL-联接父子表。如何生成此查询?_Jquery_Sql_Oracle_Join_Oracle11g - Fatal编程技术网

Jquery SQL-联接父子表。如何生成此查询?

Jquery SQL-联接父子表。如何生成此查询?,jquery,sql,oracle,join,oracle11g,Jquery,Sql,Oracle,Join,Oracle11g,我有以下表格: 我需要构建一个查询来从所有表中选择数据 我知道在A、B、C和D之间获取数据;我应该做一个左连接,但问题是当我尝试连接E和F时 是否可以在一个查询中获取所有数据?怎样 我认为一个解决方案是在a和直接子表B、C、D之间进行左连接,然后在B-E、C-E和D-F中对每一行进行内部连接,但这是一个好的解决方案吗? 任何帮助都将不胜感激 谢谢。由于未提供任何数据参考,我已为表格采用了基于级别的输入 WITH tab_a AS (SELECT 'Tab_A_' || LEVEL a_

我有以下表格: 我需要构建一个查询来从所有表中选择数据

我知道在A、B、C和D之间获取数据;我应该做一个左连接,但问题是当我尝试连接E和F时

是否可以在一个查询中获取所有数据?怎样 我认为一个解决方案是在a和直接子表B、C、D之间进行左连接,然后在B-E、C-E和D-F中对每一行进行内部连接,但这是一个好的解决方案吗? 任何帮助都将不胜感激


谢谢。

由于未提供任何数据参考,我已为表格采用了基于级别的输入

WITH tab_a AS
 (SELECT     'Tab_A_' || LEVEL a_id_a, 'Tab_A_VAL_' || LEVEL a_col_1,
             'Tab_A_VAL_' || (LEVEL + 10) a_col_2
        FROM DUAL
  CONNECT BY LEVEL <= 9),
 tab_b AS
 (SELECT     'Tab_A_' || LEVEL b_id_a, 'Tab_B_' || LEVEL b_id_b,
             'Tab_B_VAL_' || LEVEL b_col_1,
             'Tab_B_VAL_' || (LEVEL + 20) b_col_2
        FROM DUAL
  CONNECT BY LEVEL BETWEEN 1 AND 5),
 tab_c AS
 (SELECT     'Tab_A_' || LEVEL c_id_a, 'Tab_C_' || LEVEL c_id_c,
             'Tab_C_VAL_' || LEVEL c_col_1,
             'Tab_C_VAL_' || (LEVEL + 30) c_col_2
        FROM DUAL
  CONNECT BY LEVEL BETWEEN 1 AND 5),
 tab_d AS
 (SELECT     'Tab_A_' || LEVEL d_id_a, 'Tab_D_' || LEVEL d_id_d,
             'Tab_D_VAL_' || LEVEL d_col_1,
             'Tab_D_VAL_' || (LEVEL + 40) d_col_2
        FROM DUAL
  CONNECT BY LEVEL BETWEEN 1 AND 5),
 tab_e AS
 (SELECT     'Tab_B_' || LEVEL e_id_b, 'Tab_C_' || LEVEL e_id_c,
             'Tab_E_' || LEVEL e_id_e, 'Tab_E_VAL_' || LEVEL e_col_1,
             'Tab_E_VAL_' || (LEVEL + 50) e_col_2
        FROM DUAL
  CONNECT BY LEVEL BETWEEN 1 AND 3),
 tab_f AS
 (SELECT     'Tab_D_' || LEVEL f_id_d, 'Tab_F_' || LEVEL f_id_f,
             'Tab_F_VAL_' || LEVEL f_col_1,
             'Tab_F_VAL_' || (LEVEL + 60) f_col_2
        FROM DUAL
  CONNECT BY LEVEL BETWEEN 1 AND 4) SELECT   *
FROM tab_a a LEFT OUTER JOIN tab_b b ON (a.a_id_a = b.b_id_a)
     LEFT OUTER JOIN tab_c c ON (a.a_id_a = c.c_id_a)
     LEFT OUTER JOIN tab_d d ON (a.a_id_a = d.d_id_a)
     LEFT OUTER JOIN tab_e e
     ON (b.b_id_b = e.e_id_b AND c.c_id_c = e.e_id_c)
     LEFT OUTER JOIN tab_f f ON (d.d_id_d = f.f_id_d)ORDER BY 1
注意连接。当B&C不为空时,B&C与E连接。与D到F的连接相同。 希望这有帮助。

您需要选择哪些数据?你认为你问了一个完整的、独立的问题吗?