Jsf 将SelectOne菜单中的selectedValue添加到列表中

那么，交易如下： 我的视图中有一个SelectOne菜单：

<p:selectOneMenu value="#{personBean.person.personStates.state}" id="estadoRg"
    converter="entityConverter">
    <f:selectItems value="#{stateBean.states}" var="state" 
        itemLabel=#{state.name}" itemValue="#{state}">
    </f:selectItems>
</p:selectOneMenu>

您应该通过
selectedState
值来处理它，然后您可以为特定的人绑定它：

<p:selectOneMenu value="#{stateBean.selectedState}" id="estadoRg"
    converter="entityConverter">
    <f:selectItems value="#{stateBean.states}" var="state" 
        itemLabel=#{state.name}" itemValue="#{state}">
    </f:selectItems>
</p:selectOneMenu>

和支持bean方法：

public void matchStates {
    FacesContext facesContext = FacesContext.getCurrentInstance();
    ElContext elContext = facesContext.getELContext();
    Object stateBean = elContext.getELResolver().getValue(elContext, null, "stateBean"). 
    State selectedState = stateBean.getSelectedState();
    personList.get(index).setState = selectedState;
}

好啊这让我头脑清醒。。。我唯一要改变的是，该方法将由ajax处理。。。。非常感谢
public void matchStates {
    FacesContext facesContext = FacesContext.getCurrentInstance();
    ElContext elContext = facesContext.getELContext();
    Object stateBean = elContext.getELResolver().getValue(elContext, null, "stateBean"). 
    State selectedState = stateBean.getSelectedState();
    personList.get(index).setState = selectedState;
}