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将JSON从模型传递到路由不起作用_Json_Node.js_Express_Passport.js - Fatal编程技术网

将JSON从模型传递到路由不起作用

将JSON从模型传递到路由不起作用,json,node.js,express,passport.js,Json,Node.js,Express,Passport.js,我试图将一个对象从一个模型传递到我的路由,这样我就可以完成我的登录系统,但我没有收到任何东西 型号代码: const AWS = require('aws-sdk'); const bcrypt = require('bcryptjs'); const config = require('../config/config.json'); var dynamoose = require('dynamoose'); const express = require('express'); var Sc

我试图将一个对象从一个模型传递到我的路由,这样我就可以完成我的登录系统,但我没有收到任何东西

型号代码:

const AWS = require('aws-sdk');
const bcrypt = require('bcryptjs');
const config = require('../config/config.json');
var dynamoose = require('dynamoose');
const express = require('express');
var Schema = dynamoose.Schema;

const USER_SCHEMA = new Schema({
  username: {
    type: String,
    required: true
  },
  firstName: {
    type: String
  },
  lastName: {
    type: String
  },
  email: {
    type: String,
    required: true
  },
  credential: {
    type: String
  },
  password: {
    type: String,
    required: true
  }
})

const USER = module.exports = dynamoose.model('Usuarios', USER_SCHEMA);

module.exports.getUserByUsername = function (user, callback) {
  var docClient = new AWS.DynamoDB.DocumentClient();

  var params = {
    TableName: "Users",
    KeyConditionExpression: "#us = :uuuu",
    ExpressionAttributeNames: {
      "#us": "username"
    },
    ExpressionAttributeValues: {
      ":uuuu": user
    }
  };
  docClient.query(params, function (err, data) {
    if (err) {
      console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
    } else {
      data.Items.forEach(function (user, callback) {
        console.log(user.username + ": " + user.password + user.email + user.firstName);
      });
    }
    callback(null, user);
  });
}
这很好,我可以打印user.username、user.password等,但由于某些原因,我的路由器没有导入JSON

router.post('/authenticate', (req, res, next) => {
  const username = req.body.username;
  const password = req.body.password;


  USER.getUserByUsername(username, (err, user) => {
    if (err) throw err;
    if (!user) {
      return res.json({
        success: false,
        "msg": "User not found"
      });
    }
    USER.comparePassword(password, user.password, (err, isMatch) => {
      if (err) throw err;
      if (isMatch) {
        const token = jwt.sign({
          username: user
        }, secret.secret, {
          expiresIn: 86400
        });

        res.json({
          success: true,
          token: 'JWT ' + token,
          user: {
            user: user.username,
            password: USER.password,
            email: user.email
          }
        });
      } else {
        return res.json({
          success: false,
          msg: 'Wrong password'
        })
      }
    });
  });
});
comparePassword中的res.json应该是路由(即用户模型)中的对象,但没有接收到任何东西。我尝试过USER.username/email/etc USER.username/email/etc,但没有任何效果。我知道我肯定在什么地方漏掉了什么,但在哪里

这是res.json的响应

{
    "success": true,
    "token": "JWT eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VybmFtZSI6Im5pY29sYXMuZ2FyY2lhIiwiaWF0IjoxNTA5ODE5NjMxLCJleHAiOjE1MDk5MDYwMzF9.ubHbqwOZznoeR0C-FkUoX83MoYPomk5SW1ThIA7ww74",
    "user": {}
}
当然,空用户应该是用户对象


修正: 首先,我使用的是
forEach
,因此我必须传递一个索引(
user.Item[0].username
),然后我发现我可以使用一个简单的
.get
函数使用Dynamo DB查询一个项目

现在的型号:

module.exports.getUserByUsername = function (user, callback) {
  var docClient = new AWS.DynamoDB.DocumentClient();

  var params = {
    TableName: 'Users',
    Key: {
      "username": user
    }
  };

  docClient.get(params, function (err, user) {
    if (err) {
      console.error("Unable to read item. Error JSON:", JSON.stringify(err, null, 2));
    } else {
      callback(null, user);
    }
  });
}
顺便说一下,Dynamo DB将项目作为项目返回,因此我现在的路线:

USER.comparePassword(password, user.password, (err, isMatch) => {
      if (err) throw err;
      if (isMatch) {
        const token = jwt.sign({
          username: user
        }, secret.secret, {
          expiresIn: 86400
        });
        res.json({
          success: true,
          token: 'JWT ' + token,
          user: {
            user: user.Item.username,
            password: user.Item.password,
            email: user.Item.email,
            firstName: user.Item.firstName,
            lastName: user.Item.lastName,
            credential: user.Item.credential
          }
        });
      }

我还认为您必须更改comparePassword以匹配以下更改

//change comparePassword
USER.comparePassword(password, user, (err, isMatch) => {
      if (err) throw err;
      if (isMatch) {
        const token = jwt.sign({
          username: user
        }, secret.secret, {
          expiresIn: 86400
        });

        res.json({
          success: true,
          token: 'JWT ' + token,
          user: {
            user: user.username,
            password: user.password,
            email: user.email
          }
        });
      } else {
        return res.json({
          success: false,
          msg: 'Wrong password'
        })
      }
    });

当您在回调中返回用户对象时,它不在范围内

  docClient.query(params, function (err, data) {
    if (err) {
      console.error("Unable to query. Error:", JSON.stringify(err, null, 2));
    } else {
      data.Items.forEach(function (user, callback) {
        // user exists in this scope
        console.log(user.username + ": " + user.password + user.email + user.firstName);
        // something like...
        if(user) return callback(null, user)
      });
    }
    // user is undefined here
    // callback(null, user);
  });

USER.password
应该是
USER.password
?不。这很好,因为我正在通过邮递员传递用户名和密码,而express正在解析该信息,但电子邮件是问题所在。您能确认“USER.username”、“password:USER.password”是否正确吗和user.email在json和您的expressjs版本中不是空的?我发现了错误,我正在从forEach返回对象,我需要传递一个索引。响应:{“success”:true,“token”:"JWT eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.EYJ1C2VYBMFtzSi6EYJJDGVTCY6W3SiY3JLZVVVZC3Dvc3dVc3dIgIgIgIgMmKmMeKmTakingNyOf0WZHTURG91RdJJmKmZHzHzH0mKmKmKmWg2Wg2WmKmWg2WmKmKmKmWg2Wg2Wg2WmKmKmKmKmWg2Wg2Wn2Wg2Of2Of9WnWnWnWmKmKmKmKmKmKmKmKmKmKmKmKmKmKmKmWn2WnWnWnWnWnWnWnWbnqiojesilnjyw5uzwrdb3vudci6mx0simlhdci6mtuwotgymdc3mywizzhwijoxnta5ota3mtczfq.msuylqxfmojuxlkv12ypioopbzwm0helef1xtjw,“用户”:{}空用户:(