Json 找不到类型models.MpMember的ByteString反序列化程序。尝试为此类型实现隐式ByteStringDeserializer

我正在使用Etty rediscala（1.4.2）连接到Play 2.4中的Redis。我的代码如下：

override def getMember(token: String): Future[Option[Member]] = {
  redisClient.get[Member](token)
}

但是，它显示了以下错误：

找不到类型models.Member的ByteString反序列化程序。尝试为此类型实现隐式ByteStringDeserializer

我的成员如下：

case class Member(
  memberId : Long = 0l,
  email : String = "",
  firstName : Option[String] = None,
  lastName : Option[String] = None
)

object Member {
  implicit val memberReads : Reads[Member] = Json.reads[Member]
  implicit val memberWrites : Writes[Member] = Json.writes[Member]
}

---

谢谢你的帮助。

我找到了解决办法。我将Scala对象转换为Json，并将其作为字符串保存到Redis

object Member {
  implicit val byteStringFormatter = new ByteStringFormatter[Member] {
    def serialize(data: Member): ByteString = {
    ByteString(Json.toJson(data).toString)
  }

  def deserialize(bs: ByteString): Member = {
    val s = bs.utf8String
    Json.fromJson[Member](Json.parse(s)).get
  }
}

---

}我找到了解决办法。我将Scala对象转换为Json，并将其作为字符串保存到Redis

object Member {
  implicit val byteStringFormatter = new ByteStringFormatter[Member] {
    def serialize(data: Member): ByteString = {
    ByteString(Json.toJson(data).toString)
  }

  def deserialize(bs: ByteString): Member = {
    val s = bs.utf8String
    Json.fromJson[Member](Json.parse(s)).get
  }
}

---

}我找到了解决办法。我将Scala对象转换为Json，并将其作为字符串保存到Redis

object Member {
  implicit val byteStringFormatter = new ByteStringFormatter[Member] {
    def serialize(data: Member): ByteString = {
    ByteString(Json.toJson(data).toString)
  }

  def deserialize(bs: ByteString): Member = {
    val s = bs.utf8String
    Json.fromJson[Member](Json.parse(s)).get
  }
}

---

}我找到了解决办法。我将Scala对象转换为Json，并将其作为字符串保存到Redis

object Member {
  implicit val byteStringFormatter = new ByteStringFormatter[Member] {
    def serialize(data: Member): ByteString = {
    ByteString(Json.toJson(data).toString)
  }

  def deserialize(bs: ByteString): Member = {
    val s = bs.utf8String
    Json.fromJson[Member](Json.parse(s)).get
  }
}

---

}

是否希望在redis中将其序列化为JSON？或者别的什么？我想得到给定令牌作为键的值，并将该值转换为Scala成员模型您想在redis中将其序列化为JSON吗？或者别的什么？我想得到给定令牌作为键的值，并将该值转换为Scala成员模型您想在redis中将其序列化为JSON吗？或者别的什么？我想得到给定令牌作为键的值，并将该值转换为Scala成员模型您想在redis中将其序列化为JSON吗？或者别的什么？我想获得给定令牌作为键的值，并将该值转换为Scala成员模型