Json 如何解决;在Spring Boot中提取[class com.*”类型的响应时出错?
您可能想跳到下面的“我的更新2” 我有一个可以工作的RestController,因为当我直接从浏览器访问它时,它会返回JSON响应。但是,当我在不同的有界上下文中从服务发送请求时,我会得到错误:Json 如何解决;在Spring Boot中提取[class com.*”类型的响应时出错?,json,rest,spring-boot,resttemplate,http-message-converter,Json,Rest,Spring Boot,Resttemplate,Http Message Converter,您可能想跳到下面的“我的更新2” 我有一个可以工作的RestController,因为当我直接从浏览器访问它时,它会返回JSON响应。但是,当我在不同的有界上下文中从服务发送请求时,我会得到错误: {"timestamp":1579095291446,"message":"Error while extracting response for type [class com.path.to.contexttwo.client.dto.WorkerDetails] and content typ
{"timestamp":1579095291446,"message":"Error while extracting response for type
[class com.path.to.contexttwo.client.dto.WorkerDetails] and content type [application/json]; nested exception is
org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error:
Unexpected character ('<' (code 60)): expected a valid value (JSON String, Number, Array, Object or token 'null', 'true' or 'false');
nested exception is com.fasterxml.jackson.core.JsonParseException:
Unexpected character ('<' (code 60)):
expected a valid value (JSON String, Number, Array, Object or token 'null', 'true' or 'false')\n at [Source: (PushbackInputStream);
line: 1, column: 2]","details":"uri=/context-two/register-new"}
RestClient
package com.path.to.contexttwo.client;
// imports omitted, as well as other code
@Service
public class IAcessRestClientImpl implements IAcessRestClient {
private final RestTemplate restTemplate;
@Autowired
public IAcessRestClientImpl(
final RestTemplate restTemplate
) {
this.restTemplate = restTemplate;
}
@Override
public WorkerDetails getWorkerDetailsByName(final String userName) throws URISyntaxException {
Map<String,String> urlVariables = new HashMap<>();
urlVariables.put("userName", userName);
return restTemplate.getForObject(
"http://localhost:8080/iacess/get-worker-details/{userName}",
WorkerDetails.class,
urlVariables
);
}
}
WorkerDetails也存在于包com.path.to.contextone.ohs_pl中
我已经试了3天了,阅读和调试都没有用。调试器似乎显示错误发生在RestTemplate分析WorkerDetails.class时
我还尝试在所有配置类中使用ComponentScan,因为文件位于单独的包(有界上下文)中,但没有成功
我可以使用调用IAcessRestClient的类中的UserDetailsRepository来获取WorkerDetails,但这会使两个不同的有界上下文依赖于同一个数据库模式
任何帮助都将不胜感激。
我可以发布每个请求的传统代码
提前谢谢
更新
@S B请求输入参数。下面是发送参数的类:
公司服务impl
package com.path.to.contexttwo.domain.services;
// imports
@Service
public class CompanyServiceImpl implements CompanyService {
private CompanyRepository companyRepository;
private CompanyWorkerRepositoery companyWorkerRepositoery;
private WorkerDetailsClient workerDetailsClient;
private WebApplicationContext applicationContext;
@Autowired
CompanyServiceImpl (
CompanyRepository companyRepository,
CompanyWorkerRepositoery companyWorkerRepositoery,
WorkerDetailsClient workerDetailsClient,
WebApplicationContext applicationContext
) {
this.companyRepository = companyRepository;
this.companyWorkerRepositoery = companyWorkerRepositoery;
this.workerDetailsClient = workerDetailsClient;
this.applicationContext = applicationContext;
}
@Transactional
public Company criateCompany(CompanyDTO dto) throws URISyntaxException {
if (dto.getLegalyAuthorized() == true && dto.getTerms() == true) {
Company company = new Company(
dto.getCompanyName(),
dto.getStateId()
);
company = CompanyRepository.save(company);
// when saving the company, we also need some details from the current logged in user which can be
// retrieved from the idendity and access bounded context. We need those details to be saved in this context
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
String name = auth.getName();
WorkerDetails workerDetails = WorkerDetailsClient.getWorkerDetailsByName(
name
);
// ... we can't reach the rest of the code anyway, so we omitted
}
}
下面是我直接访问RestController时得到的响应:
{"userId":127,"gender":"M","firstName":"Primeiro","lastName":"Último","phoneNumber":"922222222"}
更新2
注释掉了.anyRequest().authenticated()并且所有内容都运行正常!因此,它一直都与Spring安全性有关。真遗憾。现在将尝试在启用安全性的情况下运行。由于重定向到登录页面,我收到了HTML作为响应。正确实现了身份验证(使用基本身份验证的令牌请求)一切都很顺利
谢谢大家!试试:
return restTemplate.getForObject(
"http://localhost:8080/iacess/get-worker-details/" + userName,
WorkerDetails.class);
您是否尝试将{username}替换为用户名的实际值:{username}?请共享您的输入参数和预期响应(当您从浏览器运行请求时,该选项起作用。@JavaBoy,是的,我尝试使用硬编码URI,但得到了相同的错误。实际上,在调试时,url是正确的。@SB,请查看我对问题的更新。谢谢!根据错误,响应中似乎包含一些HTML代码。请检查re中的特殊字符响应数据?谢谢,JavaBoy!实际上,这是我的第一次尝试。我碰巧根据一本书中的示例更改为当前形式。现在将恢复。
package com.path.to.contexttwo.domain.services;
// imports
@Service
public class CompanyServiceImpl implements CompanyService {
private CompanyRepository companyRepository;
private CompanyWorkerRepositoery companyWorkerRepositoery;
private WorkerDetailsClient workerDetailsClient;
private WebApplicationContext applicationContext;
@Autowired
CompanyServiceImpl (
CompanyRepository companyRepository,
CompanyWorkerRepositoery companyWorkerRepositoery,
WorkerDetailsClient workerDetailsClient,
WebApplicationContext applicationContext
) {
this.companyRepository = companyRepository;
this.companyWorkerRepositoery = companyWorkerRepositoery;
this.workerDetailsClient = workerDetailsClient;
this.applicationContext = applicationContext;
}
@Transactional
public Company criateCompany(CompanyDTO dto) throws URISyntaxException {
if (dto.getLegalyAuthorized() == true && dto.getTerms() == true) {
Company company = new Company(
dto.getCompanyName(),
dto.getStateId()
);
company = CompanyRepository.save(company);
// when saving the company, we also need some details from the current logged in user which can be
// retrieved from the idendity and access bounded context. We need those details to be saved in this context
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
String name = auth.getName();
WorkerDetails workerDetails = WorkerDetailsClient.getWorkerDetailsByName(
name
);
// ... we can't reach the rest of the code anyway, so we omitted
}
}
{"userId":127,"gender":"M","firstName":"Primeiro","lastName":"Último","phoneNumber":"922222222"}
return restTemplate.getForObject(
"http://localhost:8080/iacess/get-worker-details/" + userName,
WorkerDetails.class);