如何添加到JSON对象

我有一个JSON对象存储为php变量“$decoded_traces” 解码记录道如下所示：

{
"Coords": [
    {
        "Accuracy": "65",
        "Latitude": "53.27771684322928",
        "Longitude": "-9.01197836634846",
        "Timestamp": "Fri Jul 05 2013 11:39:15 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.27771684322928",
        "Longitude": "-9.01197836634846",
        "Timestamp": "Fri Jul 05 2013 11:39:15 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.277716230919715",
        "Longitude": "-9.01207806014157",
        "Timestamp": "Fri Jul 05 2013 11:41:16 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.277716230919715",
        "Longitude": "-9.01207806014157",
        "Timestamp": "Fri Jul 05 2013 11:41:16 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.2776809358951",
        "Longitude": "-9.012088286120322",
        "Timestamp": "Fri Jul 05 2013 11:41:22 GMT+0100 (IST)"


       }
    ]
}

我需要添加另一个名为“Image”的元素/项目/属性，它只是二进制blob的文本。所以我需要的是：

{
"Coords": [
    {
        "Accuracy": "65",
        "Latitude": "53.27771684322928",
        "Longitude": "-9.01197836634846",
        "Timestamp": "Fri Jul 05 2013 11:39:15 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.27771684322928",
        "Longitude": "-9.01197836634846",
        "Timestamp": "Fri Jul 05 2013 11:39:15 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.277716230919715",
        "Longitude": "-9.01207806014157",
        "Timestamp": "Fri Jul 05 2013 11:41:16 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.277716230919715",
        "Longitude": "-9.01207806014157",
        "Timestamp": "Fri Jul 05 2013 11:41:16 GMT+0100 (IST)"
    },
    {
        "Accuracy": "65",
        "Latitude": "53.2776809358951",
        "Longitude": "-9.012088286120322",
        "Timestamp": "Fri Jul 05 2013 11:41:22 GMT+0100 (IST)"
    }
],
"Images": [
    {
        "Image1": "binary",
        "Image2": "binary2"
    }
]
}

---

我试过一些方法，但我真的有点迷路了。显然，在添加之后，我需要再次对其进行编码，以便能够回显它。感谢所有帮助

一旦您解码了JSON，它只是一个普通的PHP关联数组。添加到它就像添加到任何其他数组一样：

$decoded_traces['Images'] = $images;

---

你是说json_解码吗？另外，我已经有一个变量decoded:$decoded_traces=json_decode（$traces，true）；因此，您的问题只是“如何添加到数组？”返回的

json\u decode（）

数组没有什么特别之处。@Baramr Ok，所以我将粘贴所有代码。我没有得到想要的输出。那是我的问题。见一分钟后的编辑JSON列表称之为invalis，但这可能与二进制文件太长有关